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3 years ago

Can someone help me with this math homework please!

Mathematics

1 answer:

Zepler [3.9K]3 years ago

8 0

Answer:

Step-by-step explanation:

1) Least common denominator of 4 and 2 is 4

To eliminate the fraction, each term should be multiplied by 4

ANS:option c

2) Mercury level of water 'y' years = Initial measure +rate of increase 'y' years

0.05 +0.1y = 0.12+0.06y

Ans : Option c

3) 4b +6 = 2 - b + 4

Add 'b' to both sides

4b + b + 6 = 2 + 4

5b + 6 = 6

Subtract 6 from both sides

5b = 6 - 6

5b = 0

b = 0

Ans : Option b

4) Maximum decimal places in this equation is 2. So, to eliminate decimal places, The equation should be multiplied by 100

Ans: option d

5) y +6 = -3y + 26

Add 3y to both the sides

y + 6 + 3y = 26

y + 3y + 6 = 26

4y + 6 = 26

Subtract 6 from both sides

4y = 26-6

4y = 20

Divide bothe sides by 4

y = 20/4

y = 5

Ans: option c

6) '2x' is subtracted from both side of the equation.

Ans: option a - subtraction property of equality

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Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

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You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

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In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .