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3 years ago

Can someone help me with this math homework please!

Mathematics

1 answer:

Zepler [3.9K]3 years ago

8 0

Answer:

Step-by-step explanation:

1) Least common denominator of 4 and 2 is 4

To eliminate the fraction, each term should be multiplied by 4

ANS:option c

2) Mercury level of water 'y' years = Initial measure +rate of increase 'y' years

0.05 +0.1y = 0.12+0.06y

Ans : Option c

3) 4b +6 = 2 - b + 4

Add 'b' to both sides

4b + b + 6 = 2 + 4

5b + 6 = 6

Subtract 6 from both sides

5b = 6 - 6

5b = 0

b = 0

Ans : Option b

4) Maximum decimal places in this equation is 2. So, to eliminate decimal places, The equation should be multiplied by 100

Ans: option d

5) y +6 = -3y + 26

Add 3y to both the sides

y + 6 + 3y = 26

y + 3y + 6 = 26

4y + 6 = 26

Subtract 6 from both sides

4y = 26-6

4y = 20

Divide bothe sides by 4

y = 20/4

y = 5

Ans: option c

6) '2x' is subtracted from both side of the equation.

Ans: option a - subtraction property of equality

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Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

3 years ago

Graph the function. y=1+0.5x

Contact [7]

Good evening ,

___________________________________________________________

To graph such function we need only 2 points that their coordinates verify the equation y=1+0.5x then we link them with a line.

Look at the photo below for the graph.

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4 years ago

Please help me with this question!!

ziro4ka [17]

Your answer would be A.) False; either both are right or one is obtuse

Two acute angles added could never equal 180

Hope this helps!

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3 years ago

In an examination it is required to get 40% of the aggregate marks to pass. A student gets 261 marks and is declared failed by 4

svetoff [14.1K]

The solution to the problem is as follows:

→x− 4% (x) = 261

→x − 4x/100 = 261

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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3 years ago

Part A:

liubo4ka [24]

Answer:

A)20 apples

B)Can only make 2 pies

C)Yes I think Is very close like probably just a lil bit more sugur but I think yes

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Step-by-step explanation:

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3 years ago