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vredina [299]
4 years ago
13

SOLVE 6^3^-X=6^2 FOR X A.X=-6B.X=1C.X=-1D.X=9​

Mathematics
1 answer:
Murrr4er [49]4 years ago
6 0
<h3>Answer: Choice B) x = 1</h3>

================================================

Explanation:

The problem should read 6^(3-x) = 6^2. The 3-x must be in parenthesis to indicate that all of "3-x" is in the exponent and not just the 3.

Because both bases are 6, and because both sides are equal, this means that the exponents must be equal as well. Therefore 3-x = 2. Let's solve for x

3-x = 2

3-x+x = 2+x .... adding x to both sides

3 = 2+x

2+x = 3 ..... flipping both sides

x+2 = 3

x+2-2 = 3-2 .... subtracting 2 from both sides

<h3>x = 1</h3>

You can use logarithms to solve this problem, but the fact that the bases are both the same allows us to use this faster shortcut.

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You can also get there using trigonometry.

  cos(60°) = 6/x

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Step-by-step explanation:

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Graph the image of this quadrilateral after a dilation with a scale factor of 4 centered at the origin
Brut [27]

Answer: The image is attached.

Step-by-step explanation:

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When the scale factor is greater than 1, the image obtained after the  dilation is greater than the pre-image and it is an "Enlargement".

When the scale factor is is between 0 and 1,  the image obtained after the  dilation is smaller than the pre-image and it is an "Reduction".

In this case we know that the scale factor is:

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You can identify that the vertices of the pre-image shown in the figure, are:

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So you need to multiply the coordinates of those vertices by 4 in order to get the coordinates of the image;

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Now you can draw it (The image is attached).

8 0
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