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3 years ago

Please let me know if these are right!!!!!!

Mathematics

2 answers:

solniwko [45]3 years ago

8 0

yes ,these are right.

natulia [17]3 years ago

3 0

Answer:

Question 1 is the third the other is right.

Step-by-step explanation:

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X^6+3x^3-5 <br> write the expression in quadratic form

Art [367]

Step-by-step explanation:

$v = {x}^{3} \\ {v}^{2} + 3v - 5 = 0 \\$

Solving this equation using the quadratic formula, we get two real solutions :

1.1926 or -4.1926

Now we know the values of v , we can calculate x since x is ∛ v

${x}^{6} + 3 {x}^{3} - 5 = 0$

$x = \sqrt[3]{1.1926} = 1.0605 \\ x = \sqrt[3]{ - 4.1926} = - 1.6125$

3 0

3 years ago

Which number completes the square? x2 − 20x + _____?

OverLord2011 [107]

100, because, x^2 - 20x + 100 = ( x - 10 )^2;

4 0

3 years ago

Can someone help me and explain? I will mark brainlest. ♡

Sedbober [7]

Answer:

$p'(4) = -3$

$q'(8) = \frac{1}{4}\\$

Step-by-step explanation:

For p'(4):

$p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)$

$p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3$

For q'(8):

$q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}$

$q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}$

4 0

4 years ago

Read 2 more answers

Use logarithms to find the exact solution for 7(17^−9)−7=49.

ch4aika [34]

ANSWER: x = -0.082

EXPLANATION:

1. Apply logarithm to both sides of the
equation. If one of the terms has base 10,
use common logarithm, otherwise, use
natural logarithm

2. Use the different properties of logarithms
to solve for the variable.

17
-92 _ 7 = 49
7.17-92 = 56
17-92 = 8
10g17(8)
-92
2
log, 7(8)
-9
log(8)
log(17)
-9
I=
-0.082
2 of 3
Add both sides by 7
Divide both sides by 7
Convert to logarithm
Divide both sides by - 9

6 0

3 years ago

Factor 60x−8460x−84 using the GCF.

PolarNik [594]

I hope this helps you

6 0

3 years ago