It is terminating it is 45/100
Answer:
The distance between them is 230.65 miles
Step-by-step explanation:
Here we use the Cosine formula

Now the distance for one hour is
= 230.65 ÷ 1
= 230.65 miles
Answer:Your poopoo
Step-by-step explanation:
Answer:
1. r+s²=49
2. pq²=24
3. -4xy-6x²+2x²y-6y= -54
Step-by-step explanation:
1. r+s²=0+7²=49
2. pq²=(6)(2)²=6(4)=24
3. -4xy-6x²+2x²y-6y= -4(3)(2)-6(3)²+2(3)²(2)-6(2)
= -24-6(9)+2(9)(2)-12
= -24-54+36-12
= -78+36-12
= -42-12
= -54
Answer:
The value of angle is 56.9°
Step-by-step explanation:
First, you have to find the length of hypotenuse using Pythagoras' Theorem, c² = a² + b² :







In order to find θ, you have to apply Sine Rule :




