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Vilka [71]
3 years ago
13

A salesperson makes a five percent commission on every sale she makes. Her daily sales in dollars) for the past 16 working days

were: 28 49 50 34 33 44 35 25 29 30 35 34 32 40 78 39. a) Find the 5 number summary and P30 b) Find the values of the standard deviation, range, and interquartile range (IQR). c) Are there any outliers? Explain!.
Mathematics
1 answer:
Novay_Z [31]3 years ago
8 0

Answer:

Step-by-step explanation:

a. The five-number summary is made up of the following summary means:

1. Minimum: 25

2. First Quartile: 30.5

3. Medium: 34.5

4. Third quartile: 43

5. Maximum: 78

6. P30: 32.1

b.

Standard Deviation: 12.72

Rank: 53

Interquartile range: 12.5

C. The interquartile range is 12.5 and 1.5 times the interquartile range is (1.5) (12.5) = 18.75. Third quartile plus 1.5 times the interquartile range is 61.75. The value of 78 exceeds 61.75, then 78 is an outlier.

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3. Consider the linear equation 2y - 3x = 5.
nignag [31]

Answer:

Step-by-step explanation:

a.

2y - 3x = 5

2(-2) - 3x = 5

-4 - 3x = 5

-3x = 9

x = -3

(-3,-2) is another solution

b.

(-1,1)

2y - 3x = 5

2(1) - 3(-1) = 5

2 + 3 = 5

5 = 5

true, the point is a solution to the equation because the equation is true after substituting x and y with the point (-1,1)

(4,1)

2y - 3x = 5

2(1) - 3(4) = 5

2 - 12 = 5

-10 = 5

not true, the point is not a solution to the equation because the equation is not true after substituting x and y with the point (4,1)

c. You can use the points from the given (-1,1) and (-3,-2) to form a line. You then shade whichever half solves the solution using points on the graph.

8 0
3 years ago
Find the nth term of 4,11,18,25...
rjkz [21]
<span>nth term = 7n - 3
n = 1,2,3,4....</span>
6 0
3 years ago
Find u, v , u , v , and d(u, v) for the given inner product defined on Rn. u = (0, −4), v = (5, 3), u, v = 3u1v1 + u2v2
tigry1 [53]

Answer:

=-12

d(u,v)=2\sqrt{31}

Step-by-step explanation:

We are given that inner product defined on R_n

=3u_1v_1+u_2v_2

u=(0,-4),v=(5,3)

We have to find the value of <u,v> and d(u,v)

We have u_1=0,u_2=-4,v_1=5,v_2=3

Substitute the value then we get

=3(0\cdot5)+(-4)(3)=-12

Now, d(u,v)=\left \|v-u\right \|

Using this formula we get

d(u,v)=\left \| (5,7) \right \|=\sqrt{3(5)^2+(7)^2}=\sqrt{75+49}=\sqrt{124}

d(u,v)=2\sqrt{31}

7 0
3 years ago
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