Answer:
F(5)
Step-by-step explanation:
its right very sorry if its late
Suppose y=0. That means
<span>x+z = 18 </span>
<span>x-z = 26/5 </span>
<span>x = 58/5 </span>
<span>z = 32/5 </span>
<span>So, the largest x can be is 58/5 </span>
<span>Now, suppose we toss in y. If we subtract y/2 from both x and z, then the difference between x and z is still 26/5, and the sum is </span>
<span>(x-y/2) + y + (z-y/2) = x+z = 18 </span>
<span>For example, if y = 4, </span>
<span>x = 48/5 </span>
<span>y = 20/5 </span>
<span>z = 22/5 </span>
<span>x-z is still 26/5, and the sum is still 18. </span>
763,400 rounded to the nearest ten thousand = 760,000....Jessie is wrong
Answer:
how about i dont
Step-by-step explanation:
translate this
fvkndfghidrhgdughdihx
Answer:
(2,21)
Step-by-step explanation:
y = 10.5x
plug 2 for x in the equation
y = 10.5(2)
then multiply 2 by 10.5
y=21
