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Genrish500 [490]
3 years ago
8

Which number below is a PRIME FACTOR of 111 A. 1 B. 111 C. 37 D. 17

Mathematics
2 answers:
Art [367]3 years ago
4 0
I think the answer is 37
katen-ka-za [31]3 years ago
4 0
C.37 I think

111 is a composite number<span>. 111 = 1 x 111 or 3 x 37. Factors of 111: 1, 3, 37, 111. Prime Factorization: 111 = 3 x 37.</span>
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. The two bottles are similar in shape. The larger bottle holds 100 m/ of perfume. Calculate how many millilitres of perfume the
FromTheMoon [43]

Answer:

The smaller bottle holds 12.5 ml of perfume.

====================

<h2>Given</h2>

  • Two bottles of similar shape;
  • Larger bottle has volume of 100 ml;
  • The length of larger bottle is 10 cm;
  • The length of smaller bottle is 5 cm.

<h2>To find </h2>

  • The volume of smaller bottle.

<h2>Solution</h2>

Find the scale factor, the ratio of corresponding dimensions:

  • k = 5/10 = 1/2

We know the volume is the function of three dimensions, therefore the ratio of volumes is the cube of the scale factor:

  • V_{small}/V_{large} = k^3\\

Substitute the known values and find the volume of small bottle:

  • V_{small}/100= (1/2)^3\\
  • V_{small}/100= 1/8
  • V_{small}= 1/8*100=12.5

The smaller bottle holds 12.5 ml of perfume.

4 0
1 year ago
Read 2 more answers
A
aleksandr82 [10.1K]

Answer:

x=67

y=40

The angles equal 63 and 117

Step-by-step explanation:

88% sure

5 0
3 years ago
Which is the last operation performed when evaluating (8-2x)+4
jek_recluse [69]
Short Answer: Combine like terms
Remark

Just from what I see here, remove the brackets first and combine like terms second.

Discussion
8 - 2x + 4     The like therms are 8 and 4 First step
12 - 2x          That's the answer. Don't go any further. 2nd and last step



3 0
2 years ago
What is the value of x? <br>10<br>15<br>30<br>45​
DochEvi [55]
X is 0,in most situations,but could you provide a picture next time?
3 0
3 years ago
The graph above represents the following polynomial function.
Korvikt [17]

Answer:

C. 0, -1, 3

Step-by-step explanation:

Note: There is no graph. I assume you mean "zeroes/roots" by "solutions".

x(x^2-2x-3)=0

/(x^2-2x-3)

x=0


x^2-2x-3 = x^2+x-3x-3 = x(x+1) + ( -3(x+1) = (x-3)(x+1)

/(x-3) --> x +1 =0, x=-1

/(x+1) --> x-3 = 0, x=3


6 0
3 years ago
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