Answer:
Step-by-step explanation:
2
(
2
x
−
1
)
+
7
<
13
Expand LHS
→
4
x
−
2
+
7
<
13
4
x
+
5
<
13
4
x
<
13
−
5
4
x
<
8
Divide through by
4
→
x
<
2
x
<
2
is represented on the real line by the interval
(
−
∞
,
2
)
This can be represented on the
x
y
−
plane by the area to the left of the vertical line
x
=
2
as graph below.
graph{2(2x-1)+7<13 [-10, 10, -5, 5]}
Solution :
Demand for cola : 100 – 34x + 5y
Demand for cola : 50 + 3x – 16y
Therefore, total revenue :
x(100 – 34x + 5y) + y(50 + 3x – 16y)
R(x,y) = 

In order to maximize the revenue, set



.............(i)


.............(ii)
Solving (i) and (ii),
4 x (i) ⇒ 272x - 32y = 400
(ii) ⇒ (-<u>) 8x - 32y = -50 </u>
264x = 450
∴ 

So, x ≈ $ 1.70 and y = $ 1.99
R(1.70, 1.99) = $ 134.94
Thus, 1.70 dollars per cola
1.99 dollars per iced ted to maximize the revenue.
Maximum revenue = $ 134.94
Answer:
27 - 50k
Simplify
1. Distribute
-5 ( 1 + 2k ) - 8 ( -4 + 5k )
-5 - 10k - 8 ( -4 + 5k )
2. Distribute
-5 - 10k - 8 ( -4 + 5k )
-5 - 10k + 32 - 40k
3. Add the numbers
-5 - 10k + 32 - 40k
27 - 10k - 40k
4. Add the same term to both sides of the equation
27 - 10k - 40k
27 - 50k
Answer:

Step-by-step explanation:
So we have the two functions:

And we want to find f(g(1)).
So, let's find g(1) first:

Substitute 1 for x:

Simplify:

Add:

So:

Now, substitute 2 for x in f(x):

Multiply:

Add:

So:

that is a very complicated question with alot of variable to figure out