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2 years ago

Plz help me well mark brainliest if correct!!.....

Mathematics

2 answers:

zvonat [6]2 years ago

6 0

A and your welcome

Sladkaya [172]2 years ago

4 0

Answer:

Step-by-step explanation:

The oil painting classes lastes two hours on Saturday

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the doctor recommended that Matt increase the number of calories you consume from 2000 to 2800 by what percent did the number of

nikdorinn [45]

Answer:

40% number of calories have increased

Step-by-step explanation:

Old Value ( Calories consume before) = 2000

New Value (increase in Calories consumed) = 2800

We need to find by what percent did the number of calories increase

To find percent increase, the formula used is:

$Percent\: increase=\frac{New\:Value-Old\:Value}{Old\:Value}\times 100%$

Putting values in formula and finding percent increase

$Percent\: increase=\frac{New\:Value-Old\:Value}{Old\:Value}\times 100\%\:\\Percent\: increase=\frac{2800-2000}{2000}\times 100\%\: \\Percent\: increase=\frac{800}{2000}\times 100\%\: \\Percent\: increase=0.4\times 100\%\: \\Percent\: increase=40\%$

So, 40% number of calories have increased

8 0

2 years ago

A rectangular building for a gym is three times as long as it is wide. Just inside the walls of the building, there is a 6ft rec

lisov135 [29]

The equation 3x² - 48x + 6856 represents the area of the gym and track together in terms of width.

<h3>What is the area of the rectangle?</h3>

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

We have:

A rectangular building for a gym is three times as long as it is wide. Just inside the walls of the building, there is a 6ft rectangular track along the walls of the gym and has an area of 7000ft²

Let x be the width of the rectangle.

As the area of track along the walls of the gym is 7000ft²

(x - 12)(3x - 12) = 7000

After simplifying:

3x² - 48x + 6856 = 0

Thus, the equation 3x² - 48x + 6856 represents the area of the gym and track together in terms of width.

Learn more about the rectangle here:

brainly.com/question/15019502

#SPJ1

3 0

1 year ago

Jen picked 3/4 of a gallon of strawberries in half an hour.If she keeps picking strawberries at the same time, how many gallons

MrRa [10]

Answer:

Number of gallons of strawberries will she have picked in 2 hours is, 3

Step-by-step explanation:

Unit rate defined as the rate are expressed as a quantity of 1, such as 4 feet per second or 6 miles per hour, they are called unit rates.

Given the statement: Jen picked 3/4 of a gallon of strawberries in half an hour.

⇒ In $\frac{1}{2}$ hour Jen picked $\frac{3}{4}$ gallon of strawberries.

Unit rate per hour = $\frac{\frac{3}{4} }{\frac{1}{2}} =\frac{3}{4} \times \frac{2}{1} = \frac{6}{4} = \frac{3}{2}$

To find the number of gallons will she have picked in 2 hours.

$Number of gallons = unit rate per hours \times 2$

= $\frac{3}{2} \times 2 = 3$

Therefore, the number of gallons will she have picked in 2 hours is, 3

6 0

2 years ago

the ratio to boys to girls in sixth grade is 5:3 if their are 400 sixth graders how many boys are their

ohaa [14]

Answer:

250 boys

Step-by-step explanation:

sum the parts of the ratio, 5 + 3 = 8 parts

Divide the total by 8 to find the value of 1 part of the ratio

400 ÷ 8 = 50 , then

number of boys = 5 × 50 = 250

7 0

1 year ago

Read 2 more answers

Pls check the attachment :) <br><br>f(x)=x^5-9x^3<br><br>

Galina-37 [17]

Answer:

As x —> negative infinity, f(x) —> negative infinity

As x —> positive infinity, f(x) —> positive infinity.

Step-by-step explanation:

$y = {x}^{5} - 9 {x}^{3}$

An odd-degree function, meaning that the graph starts from negative infinity at x —> negative infinity and positive infinity at x —> positive infinity.

As x —> negative infinity, f(x) —> negative infinity

As x —> positive infinity, f(x) —> positive infinity.

An odd-degree function is an one-to-one function so whenever x approaches positive, f(x) will also approach positive.

5 0

2 years ago