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hoa [83]
3 years ago
11

How to write 30000+300+3 in standard form​

Mathematics
1 answer:
Elis [28]3 years ago
7 0

Answer:

30303

Step-by-step explanation:

math bro

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What is the least common multiple between 8 10 and 12
DochEvi [55]
The LCM is the lowest number that is a multiple of all three numbers. 
First, list the multiples of each number
8: 8, 16, 24, 32,40 48, 56, 64, 72, 80, 88, 96, 104, 112, 120
10: 10, 20, 30 40, 50, 60, 70, 80, 90, 100, 110, 120
12: 12, 24, 36, 48, 60, 72, 84, 96, 108, 120

The LCM is 120 because there is no lower number that is a multiple of all three numbers.
Hope this helped!
3 0
3 years ago
How many 'words' can be made from the name ESTABROK with no restrictions
Bumek [7]

The number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

<h3>How to determine the number of ways</h3>

Given the word:

ESTABROK

Then n = 8

p = 6

The formula for permutation without restrictions

P = n! ( n - p + 1)!

P = 8! ( 8 - 6 + 1) !

P = 8! (8 - 7)!

P = 8! (1)!

P = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 × 1

P = 40, 320 ways

Thus, the number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.

Learn more about permutation here:

brainly.com/question/4658834

#SPJ1

6 0
1 year ago
a box contains 20 red, 10 blue and 30 yellow beads. what is the probability of a bead drawn at random being yellow or blue?​
dexar [7]

Answer:

2/3

Step-by-step explanation:

1. add all the beads up together:

    20+10+30= 60

2. add the blue and yellow beads up:

    10+30= 40

3. put 40 over 60

    40/60 which equals 2/3

4. the final answer:

    2/3

5 0
3 years ago
What is 1/4 plus 5/8
Shalnov [3]
The answer is 0.875.
5 0
3 years ago
Read 2 more answers
Suppose a jar contains 5 reds balls and 7 green balls. with eyes closed, you choose two balls at random, one after the other. wh
statuscvo [17]
The odds of getting a red first is 5/12. the odds of getting a green second is 7/11. the probability of both is then 5/12 * 7/11, or 35/132
6 0
3 years ago
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