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3 years ago

Simplify (x^3/x^2)6^2. Explain your steps. Sorry, this is the one I meant to put up.

Mathematics

1 answer:

qaws [65]3 years ago

6 0

Answer:

$36x$

Step-by-step explanation:

$\left(\frac{x^3}{x^2}\right)* \:6^2$

Apply exponent rule: $\frac{x^a}{x^b}\:=\:x^{a-b}$

$x^{3-2}*6^2$

$x*6^2$

$x*36$

$36x$

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Approximately how much money would Manny have if he invested $1,200 at an interest rate

quester [9]

Answer:

$1,701.64

Step-by-step explanation:

(see attached for reference)

recall that for compound interest, the following formula applies:

A = P [1 + (r/n) ] ^ (nt), where

A = final amount (we are asked to find this)

P = Principal amount = $1,200

r = interest rate = 5% = 0.05

t = 7 years

n = 12

Substituting these into the equation,

A = 1200 [1 + (0.05/12) ] ^ [(12)(7)]

A = $1,701.64

6 0

3 years ago

The sum of four consecutive

Firdavs [7]

Answer:

42 is the smallest of the 4 numbers.

Step-by-step explanation:

The 4 consecutive integers that total 174 are 42,43,44, and 45. Therefore, 42 is the smallest out of all 4 integers.

4 0

3 years ago

Almira earns $50 an hour. How much does she earn in 6 hours. Write a function notation for this situation

spayn [35]

Hey there,
1 hours = $ 50
6 hours = $ 50 x 6
= $300

Hope this helps :))

~Top♥

5 0

3 years ago

PLZ HURRY!!!!!!!!!!!!! Simplify. −4x^2(5x^4−3x^2+x−2)

Simora [160]

$\bold{Answer}$

$\boxed{\bold{-20x^6+12x^4-4x^3+8x^2}}$

$\bold{Explanation}$

$\bold{Simplify: \ -4x^2\left(5x^4-3x^2+x-2\right)}$

$\bold{------------------}$

$\bold{Distribute \ Parenthesis}$

$\bold{\left(-4x^2\right)\cdot \:5x^4+\left(-4x^2\right)\left(-3x^2\right)+\left(-4x^2\right)x+\left(-4x^2\right)\left(-2\right)}$

$\bold{Apply \ Addition \ / \ Subtraction \ Rules: \ +\left(-a\right)=-a,\:\:\left(-a\right)\left(-b\right)=ab}$

$\bold{-4\cdot \:5x^4x^2+4\cdot \:3x^2x^2-4x^2x+4\cdot \:2x^2}$

$\bold{Simplify \ -4\cdot \:5x^4x^2+4\cdot \:3x^2x^2-4x^2x+4\cdot \:2x^2: \ -20x^6+12x^4-4x^3+8x^2}$

$\bold{-20x^6+12x^4-4x^3+8x^2}$

$\boxed{\bold{Eclipsed}}$

5 0

3 years ago

30 POINTS!! ASAP! PLS SHOW WORK

sp2606 [1]

Answer:

QII

Step-by-step explanation:

We can use the acronym: ASTC or All Students Take Calculus.

The first letter of each word tells us details within a certain quadrant.

All trig functions in QI will be positive.

Only sine (and cosecant) will be positive in QII.

Only tangent (and cotangent) will be positive in QIII.

And only cosine (or secant) will be positive in QIV.

We know that tan(θ)<0. In other words, it's negative.

So, it our angle θ cannot be in QI or QIII.

We also know that cos(θ)<0.

So, this removes QIV, since in QIV, cosine is positive.

Therefore, the only choices that remains is QII.

In QII, sine is positive, tangent is negative, and cosine is negative.

This fits all our conditions, so θ is in QII.

And we're done!

3 0

3 years ago