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4 years ago

Simplify (x^3/x^2)6^2. Explain your steps. Sorry, this is the one I meant to put up.

Mathematics

1 answer:

qaws [65]4 years ago

6 0

Answer:

$36x$

Step-by-step explanation:

$\left(\frac{x^3}{x^2}\right)* \:6^2$

Apply exponent rule: $\frac{x^a}{x^b}\:=\:x^{a-b}$

$x^{3-2}*6^2$

$x*6^2$

$x*36$

$36x$

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Can someone please answer this question please I need it right now and please answer it correctly please show work answer number

schepotkina [342]

Answer:

24) A

22) B

Step-by-step explanation:

24)

Original Price: d

Sale: 30%

A sale means that a value is subtracted from the original price

d - 30% = 0.7d

All options given:

A) 0.3d

B) 0.7d

C) d - 0.3d = 0.7d

D) (1.0 - 0.3)d = 0.7(d) = 0.7d

All of these options are equal to the price after the sale, except A.

A is the answer to question 24

22) m > 0, n > 0 Use an example to represent m and n

m = 1, n = 2 = -0.5

-0.5 is a rational, negative number

The answer to question 22 is B

Hope this helps :)

5 0

3 years ago

I’ll give 20 points for the ans and equation.

Hunter-Best [27]

Answer: I believe it would be 1.25, because 1.42 times 55000 is 78100, and 1.25 times 64000 is 80000, and 80000 is greater than 78100.

(not completely sure though, I'm not the brightest)

Step-by-step explanation:

5 0

2 years ago

Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t

Art [367]

Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

$(AO)^2=(AD)^2-(DO)^2$

$x^{2}=5^2-3^2$

$x^{2}=25-9$

$x^{2}=16$

Upon taking square root of both sides of our equation we will get,

$x=\sqrt{16}$

$x=\pm 4$

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

$(OC)^2=(DC)^2-(DO)^2$

Upon substituting our given values we will get,

$y^2=10^2-3^2$

$y^2=100-9$

$y^2=91$

Upon taking square root of both sides of our equation we will get,

$y=\sqrt{91}$

$y\pm 9.539392$

$y\pm\approx 9.54$

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

$\text{The length of the longer diagonal}=x+y$