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Hatshy [7]
4 years ago
10

Plz helpangle r and angle t form a straight line. If angle r is 110 degrees what is angle t?

Mathematics
1 answer:
Maksim231197 [3]4 years ago
3 0

Answer:

tbh i dont even know


Step-by-step explanation:


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A certain type of brass contains 65% copper. How many pounds of copper are contained in 120 pounds of brass?
enyata [817]

The number of pounds of copper in 120 pounds of brass is = 78 pounds of copper

<h3>Calculation of number of pounds of copper</h3>

The percentage of copper in the brass = 65%

Therefore the quantity of copper in the brass = 65/100= 0.65 pounds

This means that 1 pound brass contains = 0.65 pounds of copper

The quantity of copper in 120 pounds of brass = 120 * 0.65

                                                                             = 78 pounds of copper.

Learn more about copper here:

brainly.com/question/24856041

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7 0
2 years ago
How many solutions does the system of equations below have? <br> y=2x+5<br> y=2x+5
Softa [21]

Answer:

one

Step-by-step explanation:

4 0
3 years ago
Can anyone solve ? This one is beyond me
Makovka662 [10]

Answer:

Rate = 0.13

Step-by-step explanation:

Given

y = \sqrt[3] x

Required

Determine the average rate of change over [2,7]

This is calculated as:

Rate = \frac{f(b) - f(a)}{b - a}

In this case:

b = 7 and a = 2

So, we have:

Rate = \frac{f(7) - f(2)}{7-2}

Rate = \frac{f(7) - f(2)}{5}

From the table:

f(7) = 1.91

f(2) = 1.26

Rate = \frac{1.91 - 1.26}{5}

Rate = \frac{0.65}{5}

Rate = 0.13

5 0
3 years ago
HELP!!!! A model of a volcano that is 22 cm tall with a volume of 586.7 cubic centimeters. What is the area of the base of the m
kotykmax [81]
The answer is B 80.0 cm^2
8 0
3 years ago
Read 2 more answers
The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) 5x/x^2
Olegator [25]

Given :

The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) = \dfrac{5x}{x^2+9}.

To Find :

Find the time at which the concentration is a maximum. b. Find the maximum concentration.

Solution :

For maximum value of x, K'(x) = 0.

K'(x) = \dfrac{5(x^2+9)- 5x(2x)}{(x^2+9)^2}=0\\\\5x^2+45-10x^2=0\\\\5x^2 = 45\\\\x = \pm 3

Since, time cannot be negative, so ignoring x = -3 .

Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6

Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.

Hence, this is the required solution.

5 0
3 years ago
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