Answer:
Whole numbers are all natural numbers including 0 e.g. 0, 1, 2, 3, 4… Integers include all whole numbers and their negative counterpart e.g. … -4, -3, -2, -1, 0,1, 2, 3, 4,… Where a and b are both integers.
Step-by-step explanation:
Answer:
<u>=57R1</u>
Step-by-step explanation:
the answer it's going to be remainder.
write the long division.
divide 34 by 6 and it give us 5.
then multiply the quotient digit 5 by the divisor 6.
subtract 30 from 34 and equal to 4.
bring it down the 3.
divide 43 by 6 to get 7.
multiply the quotient digit 7 by the divisor 6.
then you subtract 42 from 43.
its gave us equal to 1 it's going to be remainder 1.
Hope this helps!
-Charlie
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Okay, so if you'll want to start out by adding 300 to the 900 they want to raise. This is because they want to raise 900 dollars, and they've already spent 300 on prizes and stuff. So, they want to raise 1,200 in order to make back the money they've spent in addition to the 900 they want to make for the city park.
If they sell each ticket for $30, that means they have to sell 40 tickets to make the minimum amount of $1200.
