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mafiozo [28]
3 years ago
14

How to find distance of a vertical line on the cordinate plane

Mathematics
1 answer:
Dahasolnce [82]3 years ago
3 0
|x-y| = distance. If x = 5 and y = 1, the answer would be 4.
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Line p passes through (8, -6) and is perpendicular to the line 2x + y = -7.
kumpel [21]

Answer:

7

Step-by-step explanation:

the answer is 7 positive and negative equal positive so it is 7

5 0
2 years ago
Angle m AOC=108° m AOB=3x+4° m BOC=8x-28°<br><br> Find m AOB
Alex787 [66]

Hello from MrBillDoesMath!

Answer:

40



Discussion:

A diagram is always appreciated!

Assuming that

mAOC = mAOB    + mBOC       =>

108      = (3x + 4)  +  (8x - 28)    =>  combine common terms

108      = (3x + 8x) + (4 - 28 )     =>

108      = 11x - 24                        =>   add 24 to both sides

132     = 11x                                 =>

x = 132/11 = 12


So mAOB = 3x + 4 = 3(12) + 4 = 36 + 4 = 40



Thank you,

MrB

4 0
3 years ago
(-x2y3)*(12xy3)<br>(-2xy2)3​
Leokris [45]
Assuming the numbers are exponents expect the coefficient of 2, top expression, -12x^3y^6, multiply bottom
and= 72x^4y^8
4 0
2 years ago
Find the slope of the line passing through the points (-9, 3) and (7, -7).
Viktor [21]

Answer:

-10/16

Step-by-step explanation:

-7z3=-10 and 7-(-9)=16

6 0
2 years ago
Which one of the following is not explain why 2x+3y does not equal 5xy a. If You substitute 4 for x and 5 for y in the expressio
Irina-Kira [14]

Answer:

B. Since 2 and 3 are factors, they should be multiplied to get 6xy

Trust me

I just did it on TTM

6 0
2 years ago
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