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DedPeter [7]
3 years ago
10

If water were flowing from area a to area b via osmosis, through a semipermeable membrane, we might expect area b to be ________

in solute concentration compared to
a.
Biology
1 answer:
amid [387]3 years ago
4 0
If water were flowing from area A to area B via osmosis, through a semipermeable membrane, we might expect are B to be high in solute concentration compared to A. Osmosis is the process by which water moves from a region of a high concentration to a region of low concentration through a semipermeable membrane. It means area A is hypotonic (more water molecules than solute molecules) while area B is hypertonic (more solute molecules than water molecules). 
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Explain the reactions from
Sergio [31]

Explanation:

Glycolysis is the stage where glucose is broken down into 2 pyruvates (3 carbon compounds). This occurs in the cytoplasm and produces 2 ATP molecules. The pyruvates enters the mitochondria and enters the link reactions where it combines with co enzyme A (CoA). Decarboxylation ( removal of CO2) and dehydrogenation (removal of H) occurs here. Since CO2 is removed from the pyruvate it means a carbon is removed. This produces a 2 carbon compounds called acetyl. The acetyl compound is what combines with the CoA to form a compound called acetylCoA. This compound then enters the Krebs cycle.

The CoA co enzyme leaves and the acetyl reacts with a four carbon compound called oxaloacetate. This then forms a 6 carbon compound compound called citrate. A series of dehydrogenation and decarboxylation reactions occur to convert the 6 carbon compound back to oxalaoactate( the 4 carbon sugar). An ATP molecule is formed during one spin of the Krebs cycle.

The electron transport chain is where the reduced NAD (formed from dehydrogenation in glycolyisis, the link reactions and Krebs cycle) and Reduced FAD ( formed from dehydrogenation in the krebs cycle). molecules pass along a series of electrom carriers where they release energy that will be used to make ATP. Oxygen is the last electron carriers

I tried to sum it up as best as possible. If you want in detail explanations of each then I can explain it also.

6 0
3 years ago
Last week you were wondering what Jessica and Tom's babies might look like with respect to their eyebrows and earlobes (both Tom
mash [69]

Answer:

25%

Explanation:

The possible genotypes and phenotypes are:

  • EE or Ee: thick eyebrows
  • ee: thin eyebrows
  • FF or Ff: free earlobes
  • ff: attached earlobes

Tom and Jessica have thick eyebrows and free earlobes. Tom's mother has attached earlobes, so Tom must have inherited an <em>f</em> allele from her, and because he has free earlobes he must be heterozygous<em> Ff. </em>We assume Jessica is homozygous for free earlobes <em>FF</em>.

Tom's mother and Jessica's father have thin eyebrows, so they are both <em>ee</em> and therefore both Tom and Jessica must be heterozygous <em>Ee</em>.

From the above information, Tom has the genotype EeFf and Jessica is EeFF. If you do a Punnett Square of this cross, you'll get that the probability of having a child with free earlobes and thin eyebrows (eeF_) is 25%.

6 0
3 years ago
Which is an example of a student's breaking a safety rule when dealing with
Mumz [18]

Answer:

Explanation:

It's D

4 0
3 years ago
What is the appropriate technique to stimulate a baby to breathe?
alukav5142 [94]
One can stimulate a baby to breathe by slapping  his butt or by flicking the soles of his feet. This is normally done in order to stimulate a baby to take his first breath through the process of crying. Crying will force the baby to take his first breath and at the same time, it will enable the lungs and the airways to be cleared of liquid substances. 
4 0
3 years ago
In a covalent bond, electrons are
vivado [14]

Answer:

I think the answer would be 'bonding to each other

6 0
3 years ago
Read 2 more answers
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