3 years ago

Find the area of the triangle below. Round to the nearest hundredth.

Mathematics

1 answer:

vampirchik [111]3 years ago

4 0

Answer:

A = 48.11 cm^2

Step-by-step explanation:

A = 1/2 bh

A = 1/2 (11.32) (8.5)

A = 48.11 cm^2

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Which of the following is equvalent to (16^3/2)^1/2<br>A. 6<br>B. 8<br>C. 12<br>D. 64

bagirrra123 [75]

B. 8 is the answer.

Simplify to 2^4^(3/4) then 2^3 then that simplies to 8

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3 years ago

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The regression line for the given data is = 5.044x + 56.11. determine the residual of a data point for which x = 2 and y = 66.

iren [92.7K]

Do you have answer choices ?

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3 years ago

What is the Compound Inequality that is true for the missing side length? 3cm, 4cm, Xcm

Brrunno [24]

Answer:

$x< 3+4\: and\\\left | 3-4 \right |$

Step-by-step explanation:

1. Well, when it comes to triangles. Mainly Pythagorean Triple, right triangles whose sides are 3,4,5 or 5,11,12

2. Keeping in mind this a Pythagorean Triple, then x=5

3. Then we can write it as Compound Inequality by combining the Statements for an Inequality of Triangle:

We can write it as

$5$

Or we can do:

$4$

and:

$3$

4. Writing in terms of x:

$x$

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4 years ago

Radius = 11 cm.; Height = 10 cm.

Fittoniya [83]

Answer:

$3801.32 {cm}^{3}$

Step-by-step explanation:

$V=π {r}^{2} h \\ =π· {11}^{2} ·10 \\ ≈3801.3271$

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3 years ago

A scientist finds the distances d that two snakes travel in a time of t seconds. the equation 16t = d represents the relationshi

wlad13 [49]

From the equation given, the time for the black mamba snake to cover distance d, will be d/16 while that for the the rought-scaled snake would be d/1.5.
Assume that the distance covered by both snakes is 200 meters;
Then,
Time taken by the black mamba is 200/16 = 12.5 seconds, and
Time taken by the rought-scaled snake is 200/1.5 = 133.33 seconds
Clearly the black mamba is faster at 12.5 seconds compared with the rought-scaled snake.

4 0

3 years ago