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kvasek [131]
3 years ago
13

Why are group '0' elements called inert gas?​

Chemistry
2 answers:
Zinaida [17]3 years ago
6 0

Answer:

They are called so because they have 8 electrons in their outermost cell so they don't react.

Akimi4 [234]3 years ago
5 0

Explanation:

There are called inert gases, because they do not react with other elements.

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What is the equilibrium condition in which a gas holds all the water vapor molecules that it can?
faust18 [17]

The equilibrium state of a gas when it can hold all the molecules of water vapor is known as saturation.

<h3>Which three equilibrium conditions apply?</h3>

A solid substance subjected to three forces with divergent lines of action is in equilibrium if all three of the following three circumstances hold true:

  • Coplanar action lines are present (in the same plane)
  • The paths of action have come together (they cross at the same point)
  • These forces add up to a vector with a total of zero.
<h3>What are equilibrium's first and second conditions?</h3>

An object must satisfy two requirements of equilibrium in order to maintain static equilibrium.

  • First, there must be no net force acting on the item.
  • Second, there must be no net torque pulling on the object.

learn more aboute quilibrium condition here

<u>brainly.com/question/517289</u>

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7 0
2 years ago
Outline the steps needed to determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.
kumpel [21]

Answer : The limiting reactant is O_2

Explanation : Given,

Mass of C_3H_8 = 30.0 g

Mass of O_2 = 75.0 g

Molar mass of C_3H_8 = 44 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_3H_8 and O_2.

\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=\frac{30.0g}{44g/mole}=0.682moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{75.0g}{32g/mole}=2.34moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

From the balanced reaction we conclude that

As, 5 mole of O_2 react with 1 mole of C_3H_8

So, 2.34 moles of O_2 react with \frac{2.34}{5}\times 1=0.468 moles of C_3H_8

From this we conclude that, C_3H_8 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Therefore, the limiting reactant is O_2

5 0
3 years ago
Why does each mineral have its own properties?
ch4aika [34]
Beacause they all belong to a partcular kingdom which operates protons
3 0
3 years ago
Read 2 more answers
A solution of cough syrup contains 5.00% active ingredient by volume. If the total volume of the bottle is 11.0 mL , how many mi
Marta_Voda [28]
All you need to do is change 5% into a decimal which would be 5/100 = .05
then multiply the decimal by the total volume to get the amount of active ingredients in ml
.05 * 56ml = 2.8 ml of active ingredient.

Hope that helps!
4 0
3 years ago
Read 2 more answers
2. A 6.0 ampere light bulb operates at 120 V. What is the resistance of the bulb?
maria [59]

Answer:

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6 0
3 years ago
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