Question

Water forms according to the equation below: 2H2(g) + O2(g) 2H2O(g) Hrxn = -483.64 kJ How much energy is released during the formation of 1 mol H2O(g)?

Answer 1

Answer:

Hrxn = -241.82 kJ

Explanation:

2H2(g) + O2(g) --> 2H2O(g) Hrxn = -483.64 kJ ............. (i)

The equation for formation of 1 mol of H2O is given as;

H2(g) + 1/2O2(g) --> H2O(g) ................. (ii)

Eqn (ii) is obtained by dividing eqn (i) by 2

That means the heat of reaction for eqn (ii) is given as;

Hrxn = -483.64 kJ / 2

Hrxn = -241.82 kJ