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2 years ago

Correct ANSWER GETS BRAINLIST

Chemistry

1 answer:

Mrac [35]2 years ago

6 0

Answer:

The answer is B lose photosynthetic ability.

Explanation:

The acidity of acid rain can directly affect the plant leaves necessary for photosynthesis, and it makes the soils unable to sustain plant life as well. Instead of letting plants grow quicker it actually slows down plant growth.

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What is 606 as a 2 sig fig answer?

maksim [4K]

6, 0

thats the answer, i hope it helps

3 0

3 years ago

You want to clean a 500-ml flask that has been used to store a 0.9M solution. Each time the flask is emptied, 1.00 ml of solutio

Citrus2011 [14]

Answer:

In the 5th cycle rinse, the residual concentration of the solution is < 0.00001M

Explanation:

In each rinse cycle, the dilution that you are doing of the solution is from 1.00mL to 10.00mL, that is a dilution of 10

In the first rinse the concentration must be of 0.9M 10 = 0.09M

2nd = 0.009M

3rd = 0.0009M

4th = 0.00009M

5th = 0.000009M →

<h3>In the 5th cycle rinse, the residual concentration of the solution is < 0.00001M</h3>

4 0

3 years ago

A student is asked to standardize a solution of potassium hydroxide. He weighs out 1.08 g potassium hydrogen phthalate (KHC8H4O4

natka813 [3]

Answer:

A. 0.143 M

B. 0.0523 M

Explanation:

Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).

KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄

The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:

1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol

The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.

5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:

M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M

Let's consider the neutralization of potassium hydroxide and perchloric acid.

KOH + HClO₄ → KClO₄ + H₂O

When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.

$M_{A} \times V_{A} = M_{B} \times V_{B}\\M_{A} = \frac{M_{B} \times V_{B}}{V_{A}} \\M_{A} = \frac{0.143 M \times 10.1mL}{27.6mL}\\M_{A} =0.0523 M$

8 0

3 years ago

What mass of nitrous oxide can be formed from 48.7 g of nitrogen?

Arisa [49]

$\\ \tt\bull\rightarrowtail2 N_2+O_2\longrightarrow 2N_2O$

2mol of N_2 forms 2mol of N_2O
1mol of N_2 forms 1mol of N_2O

Moles of N_2

$\\ \tt\bull\rightarrowtail \dfrac{48.7}{14}=3.4mol$

Molar mass of N_2O=44g/mol

Mass of N_2O formed

44(3.4)=132.16g

3 0

2 years ago

Someone who is good at chemistry please help me

erastovalidia [21]

Equation#1 - Ca(s)+Cl2(g) ——> CaCl2(s)
Word equation #1- Calcium and Chlorine react to form Calcium Chloride.

Equation #2- N + I3 —-> I3N
Word Equation #2- Nitrogen and Iodine react to form nitrogen triiodine.

6 0

3 years ago