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lina2011 [118]
3 years ago
12

1. Los alumnos de 4º de ESO quieren hacer un viaje de fin de curso. Para ello deciden vender camisetas en el colegio. Compran 20

0 camisetas a un conocido proveedor por un total de 780 euros. Si los gastos de alquiler del local y de luz suponen 200 euros y el precio de las camisetas es de 12 euros. ¿Cuántas camisetas tendrán que vender para obtener un beneficio de 300 euros?
Mathematics
1 answer:
Sladkaya [172]3 years ago
8 0

Answer:

Necesitas vender 106.66 camisetas para obtener un beneficio de 300 euros.

Step-by-step explanation:

Con la información proporcionada, puedes decir que el beneficio obtenido es igual a la cantidad total obtenida al vender las camisetas menos el costo. La cantidad obtenida al vender las camisetas es igual al precio por camiseta por el número de camisetas vendidas y el costo es igual al valor pagado por las camisetas mas los gastos de alquiler y de luz. De acuerdo a esto:

Beneficio=12x-(780+200), donde x es el número de camisetas vendidas

Beneficio=12x-980

Ahora puedes reemplazar el beneficio con 300 y despejar x para encontrar las camisetas que necesitas vender para obtener un beneficio de 300 euros:

300=12x-980

300+980=12x

1280=12x

x=1280/12

x=106.66

De acuerdo a esto, la respuesta es que necesitas vender 106.66 camisetas para obtener un beneficio de 300 euros.

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Answer:

a) P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

b)P(13.848Step-by-step explanation:

Previous concepts

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

For this case we assume that the sample variance is given by S^2 and we select a random sample of size n from a normal population with a population variance \sigma^2. And we define the following statistic:

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And the distribution for this statistic is T \sim \chi^2_{n-1}

For this case we know that n =25 and \sigma^2 = 6 so then our statistic would be given by:

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Solution to the problem

Part a

For this case we want this probability:

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And we can multiply the inequality by 4 on both sides and we got:

P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

And we can use the following excel code to find it: "=1-CHISQ.DIST(36.4,24,TRUE)"

Part b

For this case we want this probability:

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If we multiply the inequality by 4 on all the terms we got:

P(3.462*4 < 4S^2 < 4*10.745)= P(13.848< \chi^2And we can find this probability like this:P(13.848And we use the following code to find the answer in excel: "=CHISQ.DIST(42.98,24,TRUE)-CHISQ.DIST(13.848,24,TRUE)"

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