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lina2011 [118]
3 years ago
12

1. Los alumnos de 4º de ESO quieren hacer un viaje de fin de curso. Para ello deciden vender camisetas en el colegio. Compran 20

0 camisetas a un conocido proveedor por un total de 780 euros. Si los gastos de alquiler del local y de luz suponen 200 euros y el precio de las camisetas es de 12 euros. ¿Cuántas camisetas tendrán que vender para obtener un beneficio de 300 euros?
Mathematics
1 answer:
Sladkaya [172]3 years ago
8 0

Answer:

Necesitas vender 106.66 camisetas para obtener un beneficio de 300 euros.

Step-by-step explanation:

Con la información proporcionada, puedes decir que el beneficio obtenido es igual a la cantidad total obtenida al vender las camisetas menos el costo. La cantidad obtenida al vender las camisetas es igual al precio por camiseta por el número de camisetas vendidas y el costo es igual al valor pagado por las camisetas mas los gastos de alquiler y de luz. De acuerdo a esto:

Beneficio=12x-(780+200), donde x es el número de camisetas vendidas

Beneficio=12x-980

Ahora puedes reemplazar el beneficio con 300 y despejar x para encontrar las camisetas que necesitas vender para obtener un beneficio de 300 euros:

300=12x-980

300+980=12x

1280=12x

x=1280/12

x=106.66

De acuerdo a esto, la respuesta es que necesitas vender 106.66 camisetas para obtener un beneficio de 300 euros.

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Write a cosine function that has an amplitude of 3, a midline of 2 and a period
marissa [1.9K]

Answer:

f(x) = 3 cos  (2Pi / period value ; x  )+ 2

or see answer using 2 as the period see answer in bold below.

Step-by-step explanation:

cosine function amplitude of 3 is  A = 3

The period is used to find B

You need to show period value as the denominator and work out from there with 2PI as a function numerator to show as 2pi / period can be a data angle

C is the adding value.

Acos (Bx) + C

A = 3

Bx =  2 pi / period

C = + 2

However f 2 is also the period found

then we just plug in 2 to above formula

f(x) = 3 cos  (2Pi / 2 ; x  )+ 2

f(x) = 3cos (x pi) + 2

6 0
3 years ago
A population of a particular yeast cell develops with a constant relative growth rate of 0.4225 per hour. The initial population
Ksju [112]

Answer: The population after 3 hours is 13.9 mill.

Step-by-step explanation:

When we have an exponential with:

A  = initial population.

r = constant relative growth rate:

t = time.

The function that models this is:

P(t) = A*e^(k*t)

In this case we know that:

A = 3.9 mill.

r = 0.4225 1.

Then the function that models the population of this yeast cell is:

P(t) = (3.9 mill)*e^(0.4225*t)

where t represents the time in hours.

Then if we want to know the population after 3 hours, we should replace t by 3.

P(3) = (3.9 mill)*e^(0.4225*3) = 13.85 mill.

And we want to round our answer to one decimal place, then we must look at the second decimal place, we can see that is a 5, so we should round up.

The population after 3 hours is 13.9 mill.

8 0
3 years ago
Sara is building a triangular pen for her pet rabbit. If two of the sides measure 8 feet and 15 feet, the length of the third si
Nesterboy [21]

Answer:

1) 13 ft

Step-by-step explanation:

1) 13+8=21 which is greater than 15. Would be a triangle.

2) 7+8=15   This would be a single line, not a triangle.

3) 3+8<15   This would be a single line, not a triangle.

2) 15+8=23   This would be a single line, not a triangle.

3 0
3 years ago
Read 2 more answers
A job candidate at a large job fair can be classified as unacceptable, provisional, or acceptable. Based on past experience, a h
svp [43]

Answer:

chisquare = 31.667

degree of freedom = 2

Step-by-step explanation:

Formula for chisquare test =  (O-E)²/E

total number observations= 60 + 25 + 15 = 100                  

Estimated E,

80% x 100 = 80

15%x100 = 15

5% x 100 = 5

chisquare =

\frac{(60-80)^{2} }{80} +\frac{(25-15)^{2} }{15}+\frac{(15-5)^{2} }{5}\\

= 5 + 6.67 + 20

= 31.667

from the calculation above the value of the chisquare statistic = 31.67

the degree of freedom is the number of samples in the test  n - 1

= 3-1

= 2

I have solve this question also in a tabular form to aid understanding in the file i uploaded.

thank you and good luck!

4 0
3 years ago
PLEASE HELP!<br> ON A TEST!<br> (Show work)
Fiesta28 [93]

Answer:

Um what is the question on the test?

6 0
3 years ago
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