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My name is Ann [436]

3 years ago

9

Question B work out angle BXC give reason for each angle you work out.

2 answers:

amm18123 years ago

4 0

Here's what I got. I hope that you understand it and can word it better than I can.

likoan [24]3 years ago

4 0

Answer:

$m \angle BXC = 70\°$

Step-by-step explanation:

According to the figure,

$\angle XBC \cong \angle AXY$ , by corresponding angles definition.

So, $m \angle XBC = 55\°$

Then, $m\angle XBC = m\angle XCB$ , by isosceles triangle theorem.

$m\angle XCB=55\°$

Now, $m\angle XBC + m\angle XCB + \angle BXC = 180\°$ , by internal angles theorem.

Replacing and solving for $\angle BXC}$ , we have

$55 +55 + m\angle BXC = 180\\m\angle BXC = 180-110=70\°$

Therefore, $m \angle BXC = 70\°$

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Answer:

Step-by-step explanation:

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$\text{degree of freedom = n - 1}$

$degree of freedom = 15- 1=14$

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$From \ X^2 \ table}$ $\text{, the critical value} X^2 \text{=0.99 for degree of freedom =14 is given by : 4.660}$

$\text{, the critical value} X^2 \text{=0.01 for degree of freedom =14 is given by : 29.141}$

$\text{Thus, the lower limit = 4.660, the upper limit = 29.141}$

$\text{the confidence interval of the standard deviation} \ \sigma \ is:$

$\sqrt{\dfrac{(n -1)s^2}{X^2_{\dfrac{\sigma}{2}}} } \le \sigma \le \sqrt{\dfrac{(n -1)s^2}{X^2_{1-\dfrac{\sigma}{2}}} }$

replacing our values:

$\sqrt{\dfrac{(15 -1)0.0937^2}{29.141} } < \sigma$

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3 years ago

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Angelina_Jolie [31]

Answer:

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10. Write a word problem for this equation:<br> n ($25) = $125

Andrei [34K]

Answer:

The word problem is "How many $25 are there in $125?"

<em></em>

Step-by-step explanation:

Given

$n(\$25) = \$125$

Required

Write a word problem for the expression

We start by solving the given equation

$n(\$25) = \$125$

Divide both sides by $25

$\frac{n(\$25)}{\$25} = \frac{\$125}{\$25}$

$n = \frac{\$125}{\$25}$

$n = 5$

This implies that there are 5, $25 in $125

<em>Hence; The word problem is "How many $25 are there in $125?"</em>

6 0

4 years ago