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Likurg_2 [28]
3 years ago
11

Jamal owes $424.04 on his credit card. He returns two items, one for $49.95 and the other for $50.42.

Mathematics
1 answer:
trasher [3.6K]3 years ago
8 0

Answer:

$400.27

Step-by-step explanation:

owes $424.04

returns an item for $49.95

-424.04 + 49.95 = -374.09

he now owes $374.09

returns an item for $50.42

-374.09 + 50.42 = -323.67

he now owes $323.67

makes a purchase of $39.19

-323.67 - 39.19 = -362.86

he now owes $362.86

makes a purchase of $37.41

-362.86 - 37.41 = -400.27

he now owes $400.27

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What is the area of a circle that has a radius of 5 meters
Xelga [282]

Answer:

78.55m^2

Step-by-step explanation:

General formula for the area of a circle is πr^2

π=3.12

r=5m

So let's apply the formula

3.142×(5)^2

3.142×25

78.55

So the area is 78.55m^2

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What is n?<br><br> A) 2.5<br><br> B)10 <br><br> C)5<br><br> D) 1.25
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Step-by-step explanation:

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A floor mat is in the shape of a parallelogram. The mat has an area of 480 sq inches. If the base of the mat is 24 inches, what
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Hope this helped! :)
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Step-by-step explanation:

|x+5|=x+5

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7 0
3 years ago
Alex took 31 exams for 5 years studying at the MaPhAs University. Each year, he took more exams than the previous year. During h
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Answer:

The fourth year he took 8 exams

Step-by-step explanation:

We must do it by trial and error:

We must start from the first year:

A = 1 exam

If the first year he took 1 exam, the last year he did 3, but this answer is not possible because the rule that the more the years pass, the more exams he does, is not fulfilled.

A = 2 exams

In this case, if it is true that each year increases, but it does not meet the total rule, since:

Year 1 = 2

Year 2 = 3

Year 3 = 4

Year 4 = 5

Year 5 = 6

2 + 3 + 4 + 5 + 6 = 20

A = 3 exams

Therefore the fifth year would be 9, therefore it would be:

Year 1 = 3

Year 2 = 4

Year 3 = 5

Year 4 = 6

Year 5 = 9

3 + 4 + 5 + 6 + 9 = 27

This means that we are missing 4 units to reach 31, therefore we must add 4 units between years 2, 3 and 4, but always bearing in mind that each year should increase with respect to the previous one.

If we add 2 exams to year 4, 1 exams to year 3 and 1 exam to year 2, we would have the following results:

Year 1 = 3

Year 2 = 5

Year 3 = 6

Year 4 = 8

Year 5 = 9

3 + 5 + 6 + 8 + 9 = 31

Which means that in the fourth year he took 8 exams

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3 years ago
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