Simply present that you would split them up as a factor of two. ( make two lines going either vertically or horizontally. place in varriations, a marble in one line and a marble in the other and then count the leftover
Answer:
First, we have to find slope. We do that by using slope formula. Once we have found slope, we have start to write our equation in slope-intercept form. To get the complete equation, we need to find the y-intercept. To do so, we simply plug in one of the coordinates given to us into our half-formed equation. We should be able to find the y-intercept and then have our complete linear equation once we write it all out.
Step-by-step explanation:
Slope-Intercept Form: y = mx + b
Slope Formula: 
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
A function could be linear or not. Is the rate of change consistent, increasing, or decreasing? Is does the symbol have one minimum value or maximum value, or several such values?
