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4 years ago

6

Need help with problems 1 through 8 please help it is due tomorrow I have to get it done before tomorrow

1 answer:

Ede4ka [16]4 years ago

6 0

1. 0.001
2. 1000
3. 0.00001
4. 0.01
5. 1
6. 10000
7. 10
8. 100000

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Which equation can be used to solve for c? Triangle A B C is shown. Angle A C B is 90 degrees and angle A B C is 35 degrees. The

aliina [53]

Answer:

The correct option is B) $c=\frac{5}{\cos35^0}$ .

Step-by-step explanation:

Consider the provided information.

Angle A C B is 90 degrees and angle A B C is 35 degrees.

The required figure is shown below:

We need to find the value of c.

Use the trigonometric function: $\cos\theta=\frac{Adjacent}{Hypotenuse}$

$\cos35^0=\frac{5}{c}$

$c=\frac{5}{\cos35^0}$

Hence, the correct option is B) $c=\frac{5}{\cos35^0}$ .

4 0

3 years ago

Read 2 more answers

Y = 2/3 x - 4 written in slope-intercept form plz hurry nee fast

ICE Princess25 [194]

It’s already written in the appropriate format.

3 0

3 years ago

Can you help me out and simplify?

Angelina_Jolie [31]

Answer:

= 1/3 * sqrt(1/2)

Step-by-step explanation:

sqrt(1/18)

We know that sqrt(a/b) = sqrt(a)/sqrt(b)

sqrt(1/18)

sqrt(1)/sqrt(18)

1/sqrt(18)

We also know that sqrt(ab) = sqrt(a) sqrt(b)

1/sqrt(18) = 1/ sqrt(9)sqrt(2)

= 1/(3sqrt(2))

= 1/3 * 1/ sqrt(2)

We know that sqrt(a/b) = sqrt(a)/sqrt(b)

= 1/3 * sqrt(1/2)

5 0

4 years ago

Find A and please include explanation please. If you don’t know please don’t write whatever to get the points

PolarNik [594]

$\bf \textit{Law of Cosines}\\\\ c^2 = a^2+b^2-(2ab)cos(C)\implies c = \sqrt{a^2+b^2-(2ab)cos(C)} \\\\\\ \cfrac{a^2+b^2-c^2}{2ab}=cos(C)\implies cos^{-1}\left(\cfrac{a^2+b^2-c^2}{2ab}\right)=\measuredangle C\\\\ -------------------------------$

$\bf \begin{cases} a=90\\ b=55\\ c=50 \end{cases}\implies cos^{-1}\left(\cfrac{b^2+c^2-a^2}{2bc}\right)=\measuredangle A \\\\\\ cos^{-1}\left(\cfrac{55^2+50^2-90^2}{2(55)(50)}\right)=\measuredangle A\implies cos^{-1}\left(\cfrac{-2575}{5500} \right)=\measuredangle A \\\\\\ 117.91634^o\approx \measuredangle A$

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3 years ago

PLEASE HELP ME WITH THESE!! i will give brainliest to best answer!!!

dimaraw [331]

Answer:

$1) {11}^{12}$

$2) {13}^{10}$

$3) {14}^{19}$

$4) {2}^{8}$

$5) {7}^{14}$

$6) {3}^{12}$

$7) {17}^{16}$

$8) {5}^{9}$

$9) {16}^{6}$

$10) {18}^{9}$

$11) {9}^{14}$

$12) {8}^{10}$

$13) {12}^{13}$

$14) {17}^{17}$

$15) {5}^{6}$

$16) {3}^{4}$

$17) {19}^{12}$

$18) {20}^{9}$

$19) {4}^{7}$

$20) {6}^{9}$

$21) {10}^{15}$

8 0

3 years ago