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Veronika [31]
4 years ago
6

Need help with problems 1 through 8 please help it is due tomorrow I have to get it done before tomorrow

Mathematics
1 answer:
Ede4ka [16]4 years ago
6 0
1. 0.001
2. 1000
3. 0.00001
4. 0.01
5. 1
6. 10000
7. 10
8. 100000
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Would the point of an intersection of two lines is:
mr Goodwill [35]
A) one solution.

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4 years ago
Write the equation in standard form of a circle with center (-7,2), tangent to the y-axis.
DerKrebs [107]

Answer:

(x+7)^{2}+ (y-2)^{2}=49

Step-by-step explanation:

It is given that circle is a tangent to y axis, which tells us that the distance between the centre point and y axis is the radius of the triangle.

Formula for equation of circle with centre (x1,y1) and radius r is

(x-x1)^{2}+ (y-y1)^{2}=r^{2}

In the given case distance between the centre and y axis is 7 units so radius would be 7 and the centre point is (-7,2),

the equation of circle is ,

(x+7)^{2}+ (y-2)^{2}=7^{2}

(x+7)^{2}+ (y-2)^{2}=49

Hence the abow equation is the circle equation.

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3 years ago
1.13-lab: temperature of soil and water
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Radiation from the sun heats the Earth's surface by means of rays that are trapped in the atmosphere and allow the Earth to have constant heat.

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3 years ago
Find an equation of the tangent line to the curve at the given point. y = 3x3 - x2 + 2, (1, 4)
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y = 7x - 3

Note the gradient of the tangent is the derivative of y at x = 1

Differentiate using the power rule

\frac{d}{dx}(ax^{n}) = nax^{n-1}

y = 3x³ - x² + 2

\frac{dy}{dx} = 9x² - 2x

x = 1 : \frac{dy}{dx} = 9 - 2 = 7 ← gradient of tangent

equation in point- slope form, using m = 7 and (a, b) = (1, 4)

y - 4 = 7(x - 1) ← point-slope form

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y = 7x - 3 ← in slope-intercept form



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3 years ago
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