Answer:
Step-by-step explanation:
Let n = the smaller of the two numbers, and since the other number is 5 more than twice the smaller number n, then ...
Let 2n + 5 = the second and larger number.
Since the sum of the two unknown numbers is 26, then we can write the following equation to be solved for n as follows:
n + (2n + 5) = 26
n + 2n + 5 = 26
Collecting like-terms on the left, we get:
3n + 5 = 26
3n + 5 - 5 = 26 - 5
3n + 0 = 21
3n = 21
(3n)/3 = 21/3
(3/3)n = 21/3
(1)n = 7
n = 7
Therefore, ...
2n + 5 = 2(7) + 5
= 14 + 5
= 19
CHECK:
n + (2n + 5) = 26
7 + (19) = 26
7 + 19 = 26
26 = 26
Therefore, the two desired numbers whose sum is 26 are indeed 7 and 19.
Answer is CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC
Answer:
=
Step-by-step explanation:

=
=
=
Answer:
48
Step-by-step explanation:
let the number be x and x + 16 the result of adding 16 to it, then
the ratio of the result to the original is
=
( cross- multiply )
4x = 3(x + 16) = 3x + 48 ( subtract 3x from both sides )
x = 48