The problem statement is not clear regarding which money is invested. We will assume it is the 80% of $8750 that is set aside for future education. That amount is
... 0.80 × $8750 = $7000
If x represents the amount invested at 7%, then the total interest earned is
... (7000 -x)×4% + (x)×7% = 420
... 280 +0.03x = 420
... x = 140/0.03 ≈ 4666.67
$4666.67 was invested at 7%.
$2333.33 was invested at 4%.
Answer:
B: 4 solutions
Step-by-step explanation:
Combining the two equations results in 2x² = 52, or x² = 26.
This equation has two solutions: x = ±√26.
As before, x² = 26. If we substitute 26 for x² in the 1st equation, we get:
26 - 4y² = 16, or 4y² = 10, or y = ±√5/2. Again: two solutions.
If we take x to be +√26, y could be ±√(5/2).
Check: is ( √26, √(5/2) ) a solution of the system?
Subbing these values into the first equation, we get:
26 - 4(5/2) = 16. Is this true?
Then 10 = 10. Yes.
Through three more checks, we find that this system has FOUR solutions.
Well 3.4 goes into the house and 12.92 is outside of it. 3.4 is a smaller number so you'd add zeros to get the 12.92 into 3.4. As you add zeros you'd take the decimals out and move them to the right two times. But u actually move the decimal first than adding zeros. Step 1: Take out the decimals. Step 2: Add the zeros. Step 3: Hope this helped.
Answer:
200+60+4
Step-by-step explanation:
200+60+4=264
