The given is that A B C D <span>x 4 = D C B A </span><span> Possible values of A are 1 or 2. It can't be 1 since the </span><span> </span><span>final result A is in unit place and 1 is not possible when we multiply any number by 4 </span><span> 2 B C D x </span><span>4 = </span><span>D C B 2</span> It is clear above, that D = 8 2 B C 8 x <span>4 = </span><span>8 C B 2</span> Possible values of B should be 1 or 2 We try B=1
2 1 C 8 x <span>4 = </span><span>8 C 1 2
</span>To find for C, you can use the equation:
(2000+100+10C+8) x 4 = 8000+100C+10+240C = 432-12 = 420 Therefore,
And for this case the answer would be 35185 the lowest 1% for the salary
Step-by-step explanation:
Let X the random variable that represent the salary, and for this case we can assume that the distribution for X is given by:
Where and
And we want to find a value a, such that we satisfy this condition:
(a)
(b)
We can use the z score again in order to find the value a.
As we can see on the figure attached the z value that satisfy the condition with 0.01 of the area on the left and 0.99 of the area on the right it's z=-2.33. On this case P(Z<-2.33)=0.01 and P(z>-2.33)=0.99
If we use condition (b) from previous we have this:
But we know which value of z satisfy the previous equation so then we can do this:
And if we solve for a we got
And for this case the answer would be 35185 the lowest 1% for the salary