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3 years ago

5

Which equation has a slope m=- 4/3

2 answers:

vesna_86 [32]3 years ago

6 0

The answer is d.........

wariber [46]3 years ago

4 0

Y=mx+b
m=slope

so it is y=-4/3x+b

d is answer

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Find the area of the figure

crimeas [40]

Try this way:
S=S₁-S₂, where S - area of the figure, S₁ - area of the triangle, S₂ - area of the quadrangle.
S=0.5*(5+2)*(5+4)-2*4=31.5-8=23.5 in.²

Answer: 23.5 in.²

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3 years ago

Find the missing triagel

MrMuchimi

Answer:

b = 8.9

Step-by-step explanation:

( 12^2 - 8^2 )

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3 years ago

I need help! please!

mamaluj [8]

Answer:

$- \frac{1}{3}$

Step-by-step explanation:

The only thing important in this question in the original equation is the slope, which is 3, the multiplyer for x. To find the opposite slope follow the steps below.

The first step is to make the original slope into a fraction.

$\frac{3}{1}$

Then flip the numerator and denominator.

$\frac{1}{3}$

Now multiply this value by -1.

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There is the opposite slope of 3.

7 0

2 years ago

Complete the table of values for this absolute value function. Then use the drawing tool(s) to graph the function. F(x)-2|x+1|-1

rusak2 [61]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the equation

$f\left(x\right)=-2|x+1|-1$

As some of the absolute rules are:

$\left|a\right|=a,\:a\ge 0$

$\:|-a|=a,\:\quad \:a>0$

NOW, let us solve!

Let us substitute all the table values

Putting x = -4

$y=-2\left|-4+1\right|-1$ ∵ $\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$y=-6-1$

$y=-7$

So, when x = -4, then y = -7

Putting x = -3

$y=-2|-3+1|-1\:$

$y=-4-1$

$y=-5$

when x = -3, then y = -5

Putting x = -2

$y=-2\left|-2+1\right|-1$

$y=-2-1$

$y=-3$

when x = -2, then y = -3

Putting x = -1

$y=-2\left|-1+1\right|-1$

$y=-0-1$

$y=-1$

when x = -1, then y = -1

Putting x = 0

$y=-2\left|0+1\right|-1$

$y=-2-1$

$y=-3$

when x = 0, then y = -3

Putting x = 1

$y=-2\left|1+1\right|-1$

$y=-4-1$

$y=-5$

when x = 1, then y = -5

The graph is also attached below.

6 0

3 years ago

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Ira Lisetskai [31]

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3 years ago

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