Remark
The basic equation is y = mx + b
y = the total amount of money
m = The amount of money he save each month (it is a constant).
b = the y intercept which is his starting amount or 120 dollars.
x = the number of months (this is a variable).
After 3 months he has 840 dollars. That's y
840 = 3*m + 120 Subtract 120 from both sides
840 - 120 = 3m
720 = 3m
240 = m So he saves 240 every month.
Now the equation becomes.
y = 240 * x + 120
Savings after 24 months
y = Total
m = 240 dollars/month
x = 24 months
b = 120
y = 24*240 + 120
y = 5760 + 120
y = 5580
He had 5580 dollars after saving for 2 years (or 24 months total) This assumes that when he started, he took his birthday money and added a 1 month payment to it
The value of x in the secants intersection is 1 units
The value of NM in the tangent and secant intersection is 51 units
<h3>How to find length when secant and tangent intersect?</h3>
The first question, two secant intersect outside the circle.
Therefore,
(6x + 8x)8x = (9 + 7)7
14x(8x) = 16(7)
112x² = 112
x² = 112 / 112
x = √1
x = 1
The second question, tangent and secant intersect,
Therefore,
(x + 3)² = (x - 3)(16 + x - 3)
(x + 3)² = (x - 3)(x + 13)
(x + 3)(x + 3) = (x - 3)(x + 13)
x² + 3x + 3x + 9 = x² + 13x - 3x - 39
x² + 9x + 9 = x² + 10x - 39
x² - x² + 9x - 10x = -39 - 9
-x = - 48
x = 48
NM = 48 + 3 = 51 units
learn more on secant and tangent here: brainly.com/question/12477905
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1,34 x( -19/37)=
1, 34 x (-0.5135) =-0,68809
<u><em>+plus -= negativo</em></u>
48
1st seat 6 possible for each 6 only 1 possible(spouse) for seat 2
3rd seat 4 possible for each 4 only 1 possible(spouse) for seat 4
5th seat 2 possible for each 2 only 1 possible(spouse) for seat 6
6 x 4 x 2 = 48
OR 3 couples possible arrangements 3 x 2 x1 = 6
each couple 2 possible 2 x 2 x 2 = 8
therefore 6 x 8 = 48
