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zzz [600]
4 years ago
9

Simplify (-10mn^3-4n^4)-(-2n^4-7mn^3-6n^3)-(5n^3+6mn^3)​

Mathematics
1 answer:
konstantin123 [22]4 years ago
4 0

Answer

-n3 • (9m + 2n - 1)

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6 4/5+5 3/10 adding and subtracting mixed number
lawyer [7]

Too add mixed numbers, first convert them to improper fractions:

34/5 + 53/10

Next, find a common denominator, which in this case is 10.

Convert 34/5 so that it has a denominator of 10 by multiplying the ENTIRE fraction by 2: 68/10

68/10 + 53/10 = 121/10

You can either give your answer in the form of an improper fraction: 121/10, or a mixed number 12 1/10

4 0
3 years ago
2a +5 - 3a -12 please
chubhunter [2.5K]

Answer:

-7-a

Step-by-step explanation:

2a-3a +5-12

-a - 7

or -7-a

7 0
3 years ago
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Lainey is sliding down a water slide that is 420 feet long at a rate of 42 feet per second. How long will it take Lainey to trav
BARSIC [14]

Answer:

10 seconds.

Step-by-step explanation:

420/42 = x amount of seconds.

It took Lainey 10 seconds.

3 0
3 years ago
) Al repartir laminas entre mis amigos, pude darle 5 a
prisoha [69]

Answer:

Había cinco amigos al principio y siete laminas en total. (Using google translate)

Step-by-step explanation:

pude darle 5 a cada = 5 amigos

5 a cada uno y me sobran 2 amigos más, por lo que las repartí de nuevo y pude darle = siete laminas

8 0
3 years ago
Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

3 0
3 years ago
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