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bezimeni [28]
3 years ago
9

During the action potential of a neuron, which ion is primarily crossing the membrane during the depolarization phase, and in wh

ich direction is the ion moving? View Available Hint(s) During the action potential of a neuron, which ion is primarily crossing the membrane during the depolarization phase, and in which direction is the ion moving?
A. K+ is entering the cell.
B. Na+ is exiting the cell.
C. Na+ is entering the cell.
D. K+ is exiting the cell.
Chemistry
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

C. Na⁺ is entering the cell.

Explanation:

In the depolarization phase, the permeability of sodium ions (Na⁺) increases, allowing a large flow of sodium ions to enter the cell through the membrane by simple diffusion.

This process causes intracellular liquids to be <u>positively</u> charged due to the large amount of cations.

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A 0.5438 g of a C.H.O. compound was combusted in air to make 1.039 g of CO2 and 0.6369 g H20. What is the empirical formula? Bal
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Answer:

C₃H₅O₂

4C₃H₅O₂ + 13O₂ → 12CO₂ + 10H₂O

Explanation:

The reaction can be expressed as:

CₓHₓOₓ + nO₂ → CO₂ + H₂O

Under the assumption that there was a total combustion, all of the carbon in the reactant was combusted into CO₂, so <u>the mass of C contained in the C.H.O. compound is the same mass of C contained in 1.039 g of CO₂</u>:

1.039gCO_{2}*\frac{1molCO_{2}}{44gCO_{2}} *\frac{1molC}{1molCO_{2}} *\frac{12gC}{1molC} =0.2834gC

All of the hydrogens atoms in the compound ended up becoming H₂O, so <u>the mass of H contained in the C.H.O. compound is the same mass of H contained in 0.6369 g of H₂O</u>:

0.6369g*\frac{1molH_{2}O}{18gH_{2}O} *\frac{1molH}{1molH_{2}O} *\frac{1gH}{1molH} =0.0354gH

Because the compound is composed only by C, H and O, <u>the mass of O in the compound can be calculated by substraction</u>:

0.5438 g Compound - 0.2834 g C - 0.0354 g H = 0.2250 g O

In order to determine the empirical formula, we calculate the moles of each component:

  • mol C = 0.2834 g C ÷ 12 g/mol = 0.0236 mol C
  • mol H = 0.0354 g H ÷ 1 g/mol = 0.0354 mol H
  • mol O = 0.2250 g O ÷ 16 g/mol = 0.0141 mol O

Then we divide those values by the lowest one:

0.0236 mol C ÷ 0.0141 = 1.67

0.0354 mol H ÷ 0.0141 = 2.51

0.0141 mol O ÷ 0.0141 = 1

If we multiply those values by 2, we're left with the empirical formula C₃H₅O₂.

  • The reaction is:

4C₃H₅O₂ + 13O₂ → 12CO₂ + 10H₂O

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3 years ago
Answer to AP chem question
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Answer:

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Explanation :

The given element is chlorine.

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Number of electrons = 17

Number of protons = 17

The electronic configuration of chloride ion is, 1s^22s^22p^63s^23p^6

Number of electrons = 18

Number of protons = 17

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