Answer:
Specific heat capacity formula
Explanation:
The heat capacity gives the exact heat energy at which a given mass of a substance is heated from one temperature to another.
This formula can help determine how much heat is gained or lost during the reaction and is given by:
Q = mcΔT
where:
Q = heat energy in Joules or Calories
m - mass of the substance (g)
c = Specific heat capacity (J/kg°C)
ΔT = change in temperature = (final temp - initial temp) (°C)
I hope this was helpful.
Answer:
L× W×H
<h2> Please mark me as brainlist. </h2>
You are given
200 grams of H2O(s) at an initial temperature of 0°C. you are also given the
final temperature of water after heating at 65°C. You are required to get the
total amount of heat to melt the sample. The specific heat capacity, cp, of
water is 4.186 J/g-°C. Let us say that T1 = 0°C and T2 = 65°C. The equation for
heat, Q, is
Q = m(cp)(T2-T1)
Q = 200g(4.186
J/g-°C )(65°C - 0°C)
<u>Q =
54,418J</u>
DiPhosphorus pentoxide or pentaoxide
The answer is oxidation.
That is in the redox fueling reaction,
succinate + NAD ↔fumarate + NADPH, the succinate molecule is undergoing oxidation.
As succinate molecule is providing electrons to NAD, so that it can be reduced from NAD to NADPH. So it is losing electrons and undergoing oxidation.
So the answer is oxidation.
