Answer:

Step-by-step explanation:
we know that
The probability that a point chosen randomly inside the rectangle is in the square is equal to divide the area of the square by the area of rectangle
Let
x-----> the area of square
y----> the area of rectangle
P -----> the probability

<em>Find the area of square (x)</em>

<em>Find the area of rectangle (y)</em>

Find the probability P

The two is in the hundreth place
Look at the number next to it, it's a five. Five rounds 2 to 3.
Your answer is 0.13
Answer:
- (0, 26)
- (-6.5, 0)
Step-by-step explanation:
Turn the equation into slope-intercept form [ y = mx + b ].
y - 6 = 4(x + 5)
y - 6 = 4x + 20
y = 4x + 26
We know that b = y-intercept for the y-intercept is 26.
Substitute 0 for y to find the x intercept.
0 = 4x + 26
-26 = 4x
-6.5 = x
Best of Luck!
Answer:
Carla needs to make at least 11 two-pointer shots in the surrent game
Step-by-step explanation:
The first thing we can do is to find the difference between the number of points that Carla scored in her first game and her second game.
This will be 46 - 24 = 22 points difference
Carla needs to make a certain number of two-pointers to get at least the same score she had in her previous game.
We can get this number of two-pointers that needed to be made by dividing the difference in scores by 2
i.e number of two-pointer shots = 22/2 =11 shots
Therefore, Carla needs to make at least 11 two-pointer shots to be able to get the same score in her current game.
Answer:
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
Step-by-step explanation:
Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.
Let five years ago be group I X and as of now be group II Y

(Two tailed test at 5% level of significance)
Group I Group II combined p
n 270 300 570
favor 120 140 260
p 0.4444 0.4667 0.4561
Std error for differene = 
p difference = -0.0223
Z statistic = p diff/std error = -1.066
p value =0.2864
Since p value >0.05, we accept null hypothesis.
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll