n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
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ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
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n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
Answer:
yes
Step-by-step explanation:
Answer:
half of 7.4 is 3.7 so the houses are 3.7 miles apart.
Answer:
72
Step-by-step explanation:
Dont worry, these problems are tricky! The answer is 72. All you have to do to find the answer is multiply 12x6. For example, if it was asking '1/8 of ... is 12' then you would multiply 12x8.
Hope this helps! I would really appreciate it if you marked me brainliest! :)
Answer:
-9
Step-by-step explanation:
You subtract 2x-6 that gives you -3
You add 3x+31 that gives you 3
You multiply your to answers -3x3
And you get -9 Hope this helps!!!!
HAVE A NICE DAY