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Annette [7]
4 years ago
15

1/6 of ... is 12. please help! hahaha nevermind i read the question wrong sorry all those smart people out there

Mathematics
2 answers:
Luba_88 [7]4 years ago
7 0
72 is the answers these problems tend to be a little tricky!! You got this!
ludmilkaskok [199]4 years ago
4 0

Answer:

72

Step-by-step explanation:

Dont worry, these problems are tricky! The answer is 72. All you have to do to find the answer is multiply 12x6. For example, if it was asking '1/8 of ... is 12' then you would multiply 12x8.

Hope this helps! I would really appreciate it if you marked me brainliest! :)

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Find the domain of f(x)= x^2+4
dusya [7]

Answer:

(Negative Infinity to Positive Infinity)

Step-by-step explanation:

A domain is all x values that can go into a function. This is a quadratic. A quadratic can accept any real number so the domain is

all \: real \: numbers

or

(Negative Infinity to Positive Infinity)

8 0
3 years ago
Northside High School is having a spaghetti dinner fundraiser. In order to advertise, students place flyers on neighborhood door
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120/120 = 1

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4 0
4 years ago
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Which of these numbers has the highest value? -22, 0.0099, 0, -1, (-1)
Oliga [24]
.0099 is the only positive number above zero and would have the highest value

5 0
3 years ago
Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the pop
Andreyy89

Answer:

The smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

Step-by-step explanation:

The complete question is:

The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,103. A sample of n people will be selected at random from those living in the city. Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income. Round your answer up to the next largest whole number.

Solution:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical value of <em>z</em> for 90% confidence level is:

<em>z</em> = 1.645

Compute the required sample size as follows:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

      n=[\frac{z_{\alpha/2}\cdot\sigma}{MOE}]^{2}\\\\=[\frac{1.645\times 2103}{500}]^{2}\\\\=47.8707620769\\\\\approx 48

Thus, the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

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3 years ago
Convert the decimal to a fraction in simplest form:
NISA [10]
0.005 = 5/1000 = 1/200
5 0
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