d = distance between the two cities
v₁ = average speed while going from chicago to kansas city = 440 knots
t₁ = time taken to travel distance going from chicago to kansas city
time taken to travel distance going from chicago to kansas city is given as
t₁ = d/v₁
t₁ = d/440 eq-1
v₂ = average speed while going from kansas city to chicago = 110 knots
t₂ = time taken to travel distance going from kansas city to chicago
time taken to travel distance going from kansas city to chicago is given as
t₂ = d/v₂
t₂ = d/110 eq-2
Given that :
t₂ = t₁ + 3
using eq-1 and eq-2
(d/110) = (d/440) + 3
d = 440
Answer:-2
Step-by-step explanation:
Answer:
40
Step-by-step explanation:
30/75 = .4
Answer:
Step-by-step explanation:
2-(-1\8)±-7\4 then
2 plus 1\8 plus -7\4
2 plus 1\8 plus -14\8
2 -13\8
2= 16/8
3\8?
39 dont forget the squared thigy
