<span>Step 1: 1.125 = 1 125⁄1000</span><span> </span>
<span>Step 2: Simplify 1 125⁄1000 = 1 1⁄8</span><span> </span>
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</span>
Answer: 9/14
Explanation. First, you have to find the least common denominator. The least common denominator is the lowest number you can use on the denominator to create a set of equivalent fractions
7 and 2 can both go into 14
Whatever number you use to multiply to equal 14, you do the same to the top.
It would look like this.
2/14 + 7/14
Then you add.
2/14 + 7/14= 9/14
You can’t simplify this fraction so this is your answer. Hope this helped!
14.50 x 2 (2 1/2 hours = 1 hour) = $29.00 + $14.50 (for another 1/2 an hour) = $43.50. Then, divide 14.50 in half for the other 15 minutes that weren't accounted for yet, so: $14.50/2 = $7.25 then add it to our previous total: $43.50 + $7.25 = $50.75 is your answer :) Hope I helped
Answer:
see explanation
Step-by-step explanation:
To multiply the vector by a scalar, multiply each of the elements by the scalar.
To add 3 vectors add the corresponding elements of each vector
2a + 3b + 4c
= 2![\left[\begin{array}{ccc}2\\3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ 3![\left[\begin{array}{ccc}-4\\1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%5C%5C1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ 4![\left[\begin{array}{ccc}3\\2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4\\6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C6%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}-12\\3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-12%5C%5C3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}12\\8\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%5C%5C8%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4-12+12\\6+3+8\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4-12%2B12%5C%5C6%2B3%2B8%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4\\17\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C17%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The answer in this question is A, D and E, we might conclude if a random sample of 36 time interval between eruption has a mean longer that 104 minutes, I can conclude that the population means may be greater than 91 and the probability mean must be more that 91, since the probability is low and also the population mean is 91, and this is an example of a typical sampling result.
