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Aliun [14]
3 years ago
10

Use the coordinates of the labeled point to find the point-slope equation of the line

Mathematics
1 answer:
koban [17]3 years ago
3 0

Answer:

A. y + 1 = -2(x-2)

Step-by-step explanation:

point-slope equation is : y - y1 = m (x -x1)

remember m= slope value

the given point is (2, -1) therefore we can substitute the values in:

y + 1 = m(x -2)

now to make sure our answer is complete we will solve for the slope:

looking back at the graph, the y-intercept value is 3, therefore we have a point of (0,3) and (2, -1)

with any two points you can determine a slope.

y2 - y1 / x2 - x1

therefore :

-1 -3 / 2 - 0

-4 / 2 = -2

therefore our m value is -2

this makes the completed point-slope equation:

y + 1 = -2 (x - 2) or A

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What equation is solved by the graphed systems of equations? 7x + 3 = x + 3 7x − 3 = x − 3 7x + 3 = x − 3 7x − 3 = x + 3
Romashka [77]
It's the first option, I'm pretty sure.
Hope this helps!!
3 0
4 years ago
What is the area of the trapezoid? 34 square units 42 square units 84 square units 118 square units.
Anvisha [2.4K]

Answer:

42 square units

Step-by-step explanation:

For a better understanding, I add an EFGH Rectangle.

The area of EFGH Rectangle = p x l

The area of EFGH Rectangle = 10 x 8

The area of EFGH Rectangle = 80cm²

The area of BHA Triangle = 1/2 x a x t

The area of BHA Triangle = 1/2 x a x t

The area of BHA Triangle = 1/2 x 6 x 4

The area of BHA Triangle = 2 x 6

The area of BHA Triangle = 12cm²

The area of AGD Triangle = 1/2 x a x t

The area of AGD Triangle = 1/2 x 4 x 2

The area of AGD Triangle = 4cm²

The area of CFD Triangle = 1/2 x a x t

The area of CFD Triangle = 1/2 x 2 x 6

The area of CFD Triangle = 6cm²

The area of BEC Triangle = 1/2 x a x t

The area of BEC Triangle = 1/2 x 8 x 4

The area of BEC Triangle = 4 x 4

The area of BEC Triangle = 16cm²

The area of the trapezoid = EFGH Rectangle - (BHA Triangle + AGD Triangle + CFD Triangle + BEC Triangle)

The area of the trapezoid = 80 - (12 + 4 + 6 + 16)

The area of the trapezoid = 80 - 38

The area of the trapezoid = 42cm²

5 0
2 years ago
Read 2 more answers
What is the least common multiple of 3,4 and 6?
olga2289 [7]

Answer:

12

Step-by-step explanation:

Write down multiples of each number:

3, 6, 9, 12 . . .

4, 8, 12 . . .

6, 12 . . .

The first one they all have is the LCM.

5 0
3 years ago
Read 2 more answers
What is the answer to this (x+3)<4
ivolga24 [154]

Answer:

x+3<4

Step 1: Subtract 3 from both sides.

x+3−3<4−3

x<1

7 0
3 years ago
Read 2 more answers
A squirrel can run a maximum speed of 12 miles per hour. At this rate how long will it take for the squirrel to run 3 miles
oksian1 [2.3K]

Answer:

Squirrel will take 0.25 hours or 15 minutes

Step-by-step explanation:

Given:

Maximum speed of squirrel = 12 miles/hour

Distance to be covered = 3 miles

To Find:

Time taken to cover the distance = ?

Solution:

We are given the distance and speed of the squirrel and we have to find the time taken by the squirrel

We are given the formula for distance

Distance = speed * time

Now to we have the values

putting in the values

3 = 12 * time

dividing both sides by 12

\frac{3}{12}=\frac{12}{12}*speed

0.25 hours = time

as one hour = 60 minutes

so

time = 0.25 * 60 minutes

time = 15 minutes

Squirrel will take 0.25 hours or 15 minutes


4 0
3 years ago
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