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jekas [21]
2 years ago
11

If there are 40 games and the team scored 1.4 goals in their games how many goals did they score?

Mathematics
2 answers:
Zina [86]2 years ago
6 0

Answer:

56 goals in 40 games

Step-by-step explanation:

I'll assume the 1.4 goals is the average per game.

(1.4 goals/game)*(40 games) = 56 goals in 40 games.

Andrei [34K]2 years ago
3 0

Answer:

56

Step-by-step explanation:

hope this helps

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A certain chalkboard manufacturer determines that their largest blackboard model has a mean length of 5.00 m and a standard devi
Igoryamba

Answer:

23 chalkboards

Step-by-step explanation:

Given:

Mean length = 5 m

Standard deviation = 0.01

Number of units ordered = 1000

Now,

The z factor = \frac{\textup{x - Mean}}{\textup{standard deviation}}

or

The z factor = \frac{\textup{4.98 - 5}}{\textup{0.01}}

or

Z = - 2

Now, the Probability P( length < 4.98 )

Also, From z table the p-value = 0.0228

therefore,

P( length < 4.98 ) = 0.0228

Hence, out of 1000 chalkboard ordered (0.0228 × 1000) = 23 chalkboard are likely to have lengths of under 4.98 m.

7 0
3 years ago
The letter tiles shown are placed in a bowl. Matt selects one tile from the bowl.
Julli [10]

Answer:

4/10 or 2/5

Step-by-step explanation:

probability of each letter:

J = 0/10

U = 2/10

M = 1/10

P =  1/10

4 0
3 years ago
Is 1/2 equivalent to 2/4
mina [271]
Yes it is because 1/4 + 1/4 =2/4 and 2/4 equals 1/2
5 0
2 years ago
Read 2 more answers
Talia uses 10 strawberries and 4 oranges to make 8 servings of fruit salad. How many strawberries for 12 servings?
gayaneshka [121]
For 8 servings, Talia uses strawberries = 10
For 1, it is = 10/8

Now, for 12 servings, it would be: 10/8 * 12 = 10/2 * 3 = 5 * 3 = 15

In short, Your Answer would be 15 strawberries

Hope this helps!
8 0
3 years ago
Whilst shopping, the probability that Caroline buys fruit is 0.4. The probability that Caroline independently buys a CD is 0.2.
AleksandrR [38]

Answer:

probability that Caroline buy both CD and  fruit = 0.52

Step-by-step explanation:

We have given that the probability of Caroline buys a fruit P = 0.4

So probability of Caroline does not buy the fruit = 1 - 0.4 = 0.6

Probability Caroline buys a CD P = 0.2

So probability of Caroline does not buy the CD = 1 - 0.2 = 0.8

So probability that Caroline does not buy either buy CD or fruit = 0.8×0.6=0.48

So probability that Caroline buy both CD and  fruit =1-0.48 = 0.52

7 0
3 years ago
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