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jekas [21]
2 years ago
11

If there are 40 games and the team scored 1.4 goals in their games how many goals did they score?

Mathematics
2 answers:
Zina [86]2 years ago
6 0

Answer:

56 goals in 40 games

Step-by-step explanation:

I'll assume the 1.4 goals is the average per game.

(1.4 goals/game)*(40 games) = 56 goals in 40 games.

Andrei [34K]2 years ago
3 0

Answer:

56

Step-by-step explanation:

hope this helps

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Maggie took her dad out to lunch for his birthday. Their lunch cost $23, and the local sales tax is 9%. If Maggie left a 20% tip
kicyunya [14]

Answer:

29.67

Step-by-step explanation:

Here's the explanation if you need it,

First, miltiply 9% by 23 thats your tax

next, multiply 20% and 23

Then take all the values you got and add them all togeather hope that helps!

3 0
3 years ago
Read 2 more answers
Alan needs to read 4 novels each month Let N be the number of novels Alan needs to read in M months. Write an equation relating
MaRussiya [10]

Answer:

T=N*M and he needs to read 44 books.

Step-by-step explanation:

Note: Let T represent the total amount of books that Alan needs to read in 11 months.

If we plug in the information we have been given we will find the total:

T=N*M

T=4*11

T=44

Alan has to read 44 books within a 11 month period.

Please consider giving a thanks, a good rating, and Brainliest. It is always greatly appreciated! Thanks!

6 0
3 years ago
Tom is using logarithms to solve the equation 3^2x = 32. Which of the following equations would be equivalent to his original ex
Trava [24]
3^(2x)=32  so taking log of both sides

2x*log3=log32
5 0
3 years ago
Read 2 more answers
A sandwich shop loses $1.20 every time somebody buys a sandwich, but makes $1.80 every time somebody buys a drink. One day, the
levacccp [35]

Answer:

A, B, and C

I think. Please let me know if wrong.

Heres what i did:

1.8 x 100 = 180.

180 - 80 = 100

(they made over 100 in profit)

A. 1.2 x 0 = 0

B. 1.2 x 40 - 48

C. 1.2 x 60 = 72

D. 1.2 x 70 = 84

E. 1.2 x 80 =96

D and E bot Exceed 80 so it has to be AB and C

Hope this Helps ☺

6 0
4 years ago
A store sells candy at $.50, $1, $1.50, $2, and $3 per kilogram. You can see that the unit price of candies and the amount of ca
Alecsey [184]

Answer:

Constant of variation = 3

Step-by-step explanation:

Given that a store is selling different candies costing  $.50, $1, $1.50, $2, and $3 per kilogram.

As given

Amount available to buy candies = $ 3

Suppose

Unit price of candies = x

Number of candies bough = y

Constant of variation = k

As we know the unit price of candies and number of candies bought vary inversely. As the unit price would increase the the number of candies bought in available amount ($3) would decrease.

So our formula to calculate formula for constant of variation would be as shown below:

k= xy →(1

Case 1

if we take unit price x to be $0.5, then we can buy 6 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (0.5)(6) = 3

Case 2

if we take unit price x to be $1, then we can buy 3 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1)(3) = 3

Case 3

if we take unit price x to be $1.5, then we can buy 2 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1.5)(2) = 3

Case 4

if we take unit price x to be $2, then we can buy 1.5 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (2)(1.5) = 3

Case 4

if we take unit price x to be $3, then we can buy 1 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (3)(1) = 3

So, our constant of variation is 3.

4 0
4 years ago
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