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damaskus [11]
3 years ago
8

Which set of ordered pairs could be generated by an exponential function? A)(negative 1, negative one-half), (0, 0), (1, one-hal

f), (2, 1) B) (–1, –1), (0, 0), (1, 1), (2, 8) C) (negative 1, one-half), (0, 1), (1, 2), (2, 4) D)(–1, 1), (0, 0), (1, 1), (2, 4)
Mathematics
2 answers:
Vadim26 [7]3 years ago
3 0

Answer:

<h2>C) (negative 1, one-half), (0, 1), (1, 2), (2, 4)</h2>

Step-by-step explanation:

The set C could be generated by an exponential function. The main reason is that exponential functions hava a restricted range, it can't have negative numbers or the number zero, because power can only be equal or greater than 1.

Additionally, for all exponentials, a null exponent gives 1 as an answer, so point (0, 1) is always present in an exponential function.

Therefore, the right answer is C.

Tamiku [17]3 years ago
3 0

Answer:

C

Step-by-step explanation:

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Zolol [24]

Answer:

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Step-by-step explanation:

Notice that in order to solve this problem  (find angle JLF) , we need to find the value of the angle defined by JLG and subtract it from 180^o, since they are supplementary angles. So we focus on such, and start by drawing the radii that connects the center of the circle (point "O") to points G and H, in order to observe the central angles that are given to us as 90^o and 138^o. (see attached image)

We put our efforts into solving the right angle triangle denoted with green borders.

Notice as well, that the triangle JOH that is formed with the two radii and the segment that joins point J to point G, is an isosceles triangle, and therefore the two angles opposite to these equal radius sides, must be equal. We see that angle JOH can be calculated by : 360^o-90^o-138^o=132^o

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3 years ago
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