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baherus [9]
3 years ago
7

STRUCTURE Without graphing or solving, determine the number of solutions of the system.

Mathematics
1 answer:
Mkey [24]3 years ago
6 0
I believe the answer would be "infinitely many solutions" because you can put any number as x and y would be a different answer each time for both of the equations given. i hope this helps :)
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Write the expression in expanded form that is equivalent to 3(7d +4e)
pickupchik [31]

Answer:

21+4

Step-by-step explanation:

3 times 7=21

3 times4=12

21d+4e

4 0
2 years ago
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7m + 3mn when m = 8 and n = 14
Kazeer [188]

Answer:

392

Step-by-step explanation:

m = 8 and n = 14

Substituting the values of m and n in the question, we get :

7m + 3mn

=( 7 x 8) +(3 x 8 x 14)

= 56 + 336

= 392

8 0
3 years ago
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Keisha solved the following equation: 4x − 2x + 8 = 6(x + 4) Step Work Justification 1 2x + 8 = 6(x + 4) Combine like terms 2 2x
kolbaska11 [484]

4x - 2x + 8 = 6(x + 4)   Given

(4x - 2x) + 8 = 6(x + 4)

2x + 8 = 6(x + 4)     Combine like terms

2x + 8 = (6)(x) + (6)(4)

2x + 8 = 6x + 24    Distributive Property

2x - 6x + 8 = 6x - 6x + 24

-4x + 8 = 24      Subtraction Property of Equality

-4x + 8 - 8 = 24 - 8

-4x = 16    Subtraction Property of Equality

-4x : (-4) = 16 : (-4)

x = -4       Division Property of Equality

4 0
3 years ago
Find an equation of the line that satisfies the given condition. (Let x be the independent variable and y be the dependent varia
NeTakaya

Answer:

y = 4

Step-by-step explanation:

  • A line parallel to the x-axis has the same value of the <em>dependent variable (y)</em> for all the values of the <em>independent variable (x)</em>.  Hence, the line would be an <u>horizontal line that  passes through the y-axis and never meets the x-axis</u>. Since this line satisfies the condition of passing through the coordenates (x,y), (-6,4), then the equation is equal to the value of the coordinate y.  

 

Therefore, the equation of a line that satisfies these two conditions is <em>y = 4</em>.

Download pdf
8 0
3 years ago
How do you solve this ?
TEA [102]

JK=9x-11\\KL=5x+2\\JL=(9x-11)+(5x+2)=(9x+5x)+(-11+2)=14x-9\\\\JK+KL=JL\\\\\text{substitute}\\\\14x-9=10x+7\ \ \ \ |+9\\\\14x=10x+16\ \ \ \ |-10x\\\\4x=16\ \ \ \ |:4\\\\x=4\\\\JK=9x-11\to JK=9(4)-11=36-11=25

4 0
3 years ago
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