An observer (O) spots a plane flying at a 35° angle to his horizontal line of sight. If the plane is flying at an altitude of 17
2 answers:
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Answer:
(a) F(A, B, C) = AB'C' + A'BC' + A'B'C
(b) F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)
Step-by-step explanation:
(a) If F(A, B, C) = 1 iff exactly one of the coins is heads, then either
A is heads and the others are tails (AB'C')
B is heads and the others are tails (A'BC')
C is heads and the others are tails (A'B'C)
Hence, as a minterm expansion,
F(A, B, C) = AB'C' + A'BC' + A'B'C
(b) To get the corresponding maxterm expansion, we convert to binary.
The maxterm is the product of the complements.
Expanding,
F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)
Put the equation given in the form 
The center will be (-f, -g)
The center will be (-f, -g)
A square pyramid is called like so because its base is a square.
notice this one, its base is a 0.4x0.4 square, and the triangular faces have a base of 0.4 and an altitude or height of 5.
so we can simply get the area of the base and all four triangular faces and sum them up, and that's the surface area of the pyramid.
![\bf \stackrel{\textit{squarish base}}{(0.4\cdot 0.4)}~~+~~\stackrel{\textit{4 triangles}}{4\left[\cfrac{1}{2}(0.4)(5) \right]}\implies 0.16~~+~~4\implies 4.16](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bsquarish%20base%7D%7D%7B%280.4%5Ccdot%200.4%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7B4%20triangles%7D%7D%7B4%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%280.4%29%285%29%20%20%5Cright%5D%7D%5Cimplies%200.16~~%2B~~4%5Cimplies%204.16)
notice this one, its base is a 0.4x0.4 square, and the triangular faces have a base of 0.4 and an altitude or height of 5.
so we can simply get the area of the base and all four triangular faces and sum them up, and that's the surface area of the pyramid.