Given:
Total amount = $10
Cost of loaf of bread = $3.25
Cost of cheese = $5.99 per pound
Each slice weights = 0.04 pounds.
To find:
The inequality for the number of slices that Paul can afford to buy.
Solution:
Let x be the number of slices that Paul can afford to buy.
Weight of on slice is 0.04 pounds. So, weight of x slices is 0.04x pound.
Cost of cheese = $5.99 per pound
So, total cost of cheese for x slices = $5.99 × 0.04x
Now, Paul has $10 to buy bread and cheese for sandwiches. Cost of loaf of bread is $3.25.
![3.25+(5.99\times 0.04x)\leq 10](https://tex.z-dn.net/?f=3.25%2B%285.99%5Ctimes%200.04x%29%5Cleq%2010)
![0.2396x\leq 10-3.25](https://tex.z-dn.net/?f=0.2396x%5Cleq%2010-3.25)
![0.2396x\leq 6.75](https://tex.z-dn.net/?f=0.2396x%5Cleq%206.75)
Divide both sides by 0.2396.
![x\leq \dfrac{6.75}{0.2396}](https://tex.z-dn.net/?f=x%5Cleq%20%5Cdfrac%7B6.75%7D%7B0.2396%7D)
![x\leq 28.172](https://tex.z-dn.net/?f=x%5Cleq%2028.172)
The maximum integer value of x is 28.
Therefore, the required inequity is
and 28 number of slices Paul can afford to buy.