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The sample size must be 543 so the sample proportion is will not differ by 5%
We are given the following in the question:
Margin of error = 5%
Confidence interval:
p ±z√(p'(1 - p')/n)
Margin of error =
p = ±z√(p'(1 - p')/n)
Since no particular proportion is given, we take
p' = 0.5
Z critical at α 0.02 is ± 2.33
Putting values, we get,
p = ±z√(p'(1 - p')/n)
2.33 x √(0.5(1 - 0.5)/n)
√n = 2.33x 0.5/0.05
n = 542.89 = 543
Thus, the sample size must be 543 so the sample proportion is will not differ by 5%
To learn more about confidence interval refer here
brainly.com/question/15712887
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