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4 years ago

12

Suppose △DEF≅△MNO.

1 answer:

mixas84 [53]4 years ago

6 0

The answer is b. would u like to see steps or are you good?

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the selling price for a refrigerator is 584 if the mark up is 25% of the dealers cost, what is the dealers cost of the refrigera

tia_tia [17]

25% of 584 is 146. If you meant to say "25% off of the dealer's cost", the answer would be $438, since you're finding what 25% of the original price is (146) and subtracting it from the original price. The equation would be 584 - 146 = 438. I hope this helped <3

5 0

4 years ago

Read 2 more answers

The probability of event A is 0. 48, the probability of event A and B is 0. 21, and the probability of events A or B is 0. 89. W

Mice21 [21]

Probabilities are used to determine the chances of an event

The probability of event B is 0.62

The probabilities are given as:

$\mathbf{P(A) = 0.48}$

$\mathbf{P(A\ and\ B) = 0.21}$

$\mathbf{P(A\ or\ B) = 0.89}$

To calculate the probability of event B, we make use of the following formula

$\mathbf{P(A\ and\ B) = P(A) + P(B) - P(A\ or\ B)}$

So, we have:

$\mathbf{0.21 = 0.48 + P(B) - 0.89}$

Collect like terms

$\mathbf{P(B)= -0.48 +0.21 + 0.89}$

$\mathbf{P(B)= 0.62}$

Hence, the probability of event B is 0.62

Read more about probabilities at:

brainly.com/question/11234923

7 0

3 years ago

If 40% of x + 20% of x + 1/10 = 75% of x, then find the value of x. Please give answers with steps

tatyana61 [14]

Answer:

x = 13/12

Step-by-step explanation:

explain on image

3 0

3 years ago

Read 2 more answers

Find the derivative of the function at P 0 in the direction of A. f(x,y,z) = 3 e^x cos(yz), P0 (0, 0, 0), A = - i + 2 j + 3k

Alik [6]

The derivative of $f(x,y,z)$ at a point $p_0=(x_0,y_0,z_0)$ in the direction of a vector $\vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k$ is

$\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}$

We have

$f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k$

and

$\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}$

Then the derivative at $p_0$ in the direction of $\vec a$ is

$3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}$

3 0

4 years ago

I need help plz can someone help

Evgesh-ka [11]

Answer:I can’t I sorry I don’t know this question

Step-by-step explanation:

8 0

3 years ago