All categories

3 years ago

A nail salon raises their price for nails from $25 to $30. What is the percent increase?

2 answers:

6 0

Answer:
17%

step-by-step explanation:
5 out of 30 is 17%
5/30 = 5 ÷ 30 = .16... which rounds to .17 and is equal to 17%.

vekshin13 years ago

4 0

Answer:

17%

Step-by-step explanation:

5 out of 30 is 17%

5/30 = 5 ÷ 30 = .16. rounds to .17 =17%

You might be interested in

The given data set shows the weight in pounds of nine dogs at an animal hospital. Which data value is considered an outliner

nignag [31]

Where is the given data?

3 0

3 years ago

Simplify the expression below. 3 · -8 + 5 - 4 ÷ 2 -11.5 -21 -12.5 -27

Andrej [43]

-21 is your answer
hope this helps!

7 0

3 years ago

Read 2 more answers

A sign on the gas pumps of a chain of gasoline stations encourages customers to have their oil checked with the claim that one o

ELEN [110]

Answer:

a) 0.4219 = 42.19% probability that one out of the next four cars needs oil.

b) 0.3115 = 31.15% probability that two out of the next eight cars needs oil.

c) 0.2581 = 25.81% probability that three out of the next 12 cars need oil.

Step-by-step explanation:

For each car, there are only two possible outcomes. Either they need oil, or they do not need it. The probability of a car needing oil is independent of any other car, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

One out of four cars needs to have oil added.

This means that $p = \frac{1}{4} = 0.25$

a. One out of the next four cars needs oil.

This is P(X = 1) when n = 4. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{4,1}.(0.25)^{1}.(0.75)^{3} = 0.4219$

0.4219 = 42.19% probability that one out of the next four cars needs oil.

b. Two out of the next eight cars needs oil.

This is P(X = 2) when n = 8. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{8,2}.(0.25)^{2}.(0.75)^{6} = 0.3115$

0.3115 = 31.15% probability that two out of the next eight cars needs oil.

c.Three out of the next 12 cars need oil.

This is P(X = 3) when n = 12. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{12,3}.(0.25)^{3}.(0.75)^{9} = 0.2581$

0.2581 = 25.81% probability that three out of the next 12 cars need oil.

6 0

3 years ago

Sam made 2/3 liter of punch and 3/4 liter of tea to take to a party. How many liters of bervages did sam bring to the party?

JulsSmile [24]

First, what you have to do, is make like denominators of 2/3 and 3/4.

That leaves you with 8/12 and 9/12.

Now, you add those up to get 17/12.

Your answer as a mixed number: 1 5/12
Your answer as a an improper fraction: 17/12
Your answer as a decimal: 1.4166666....

Hope this Helps!

~JaredEkey

4 0

3 years ago

Read 2 more answers

Find an equation of the tangent to the curve at the given point by two methods:

Anna007 [38]

Answer:

1) y = 2x + 1

2) y = 2x + 1

Step-by-step explanation:

The parametric equation given is;

x = 1 + ln t and y = t² + 2 at (1, 3)

1) without eliminating the parameter;

Using, x = 1 + ln t ;

dx/dt = 1/t

Using y = t² + 2;

dy/dt = 2t

Slope which is dy/dx is gotten from;

dy/dx = (dy/dt)/(dx/dt)

dy/dx = 2t/(1/t)

dy/dx = 2t²

For x = 1 + In t, at x = 1, we have;

1 = 1 + In t

In t = 0

t = 1

For y = t² + 2, at y = 3, we have;

3 = t² + 2

t² = 3 - 2

t² = 1

t = ±1

Since t = ±1, then;

dy/dx = 2(±1)²

dy/dx = 2

Equation of the tangent is;

y - 3 = 2(x - 1)

y - 3 = 2x - 2

y = 2x - 2 + 3

y = 2x + 1

2) By eliminating the parameter

x = 1 + In t

Let's make t the subject of the equation.

In t = x - 1

t = e^(x - 1)

Let's put e^(x - 1) for t in y = t² + 2

Thus;

y = e^(x - 1)² + 2

y = e^(2(x - 1)) + 2

Thus, parameter has been eliminated

Equation of the tangent is gotten from;

y - y1 = m(x - x1)

m is gradient = dy/dx = 2e^(2(x - 1))

at (1, 3), we have x = 1. Thus;

m = 2e^(2(1 - 1))

m = 2e^0

m = 2

Thus, equation of tangent at (1,3) is;

y - 3 = 2(x - 1)

y - 3 = 2x - 2

y = 2x - 2 + 3

y = 2x + 1

6 0

3 years ago