Select ALL of the following scenarios that can be modeled by the equation 3t−6=17 .

1 answer:

4 0

The answer is: <span>If you triple the number of miles Karin lives from the school and then add six, you get 17 miles.</span>

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The fifth graders are planning a pizza party. Each fifth grader will eat two slices of pizza with a favorite topping. One-half o

icang [17]

32 students choose a favorite topping for their slices.

Let x be the total number of students.

1/2 of the total students, or 1/2x, choose pepperoni.
1/4 of the total students, or 1/4x, choose extra cheese.
1/8 of the total students, or 1/8x, choose sausage.
4 students choose mushrooms.

We know that together, these equal the total number of students, x:
1/2x+1/4x+1/8x+4=x

We will use 8 as the common denominator:
4/8x+2/8x+1/8x+4=x

Combining like terms:
7/8x+4=x

Subtract 7/8x from both sides:
7/8x+4-7/8x=x-7/8x
4=1x-7/8x
4=1/8x

Divide both sides by 1/8:
4÷(1/8) = 1/8x÷(1/8)
4/1÷(1/8) = x
4/1×8/1 = x
32/1 = x
32 = x

4 0

3 years ago

Please help! I don't understand how to solve this problem

Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

The margin of error is:

$M = z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

$S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547$

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.