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vfiekz [6]
3 years ago
5

Six students eat 6 apples in 33 seconds. How long will it take nine students to eat 19 apples, if they don't cut apples into par

ts?
Mathematics
1 answer:
stepladder [879]3 years ago
3 0

Answer: 104.5 seconds

Step-by-step explanation:

Hi, to answer this question we have to apply proportions:

Six students eat 6 apples in 33 seconds.

The proportion is: number of apples eaten /time

6 apples /33 seconds = 6/33

For 19 apples:

19 apples / x seconds =19/x

6/33 = 19/x

Solving for x:

x = 19 / ( 6/33)

x = 104.5 seconds

Feel free to ask for more if needed or if you did not understand something.

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5x^2-2x=2<br>help plsmmm​
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Answer:

Presumably you're solving for x here?  Without further information we'll assume that.

With that in mind, x is approximately equal to 0.86 and -0.46

Step-by-step explanation:

Let's start by putting it in the usual ax² + bx + c format.

5x^2- 2x = 2\\5x^2 - 2x - 2 = 0\\

let's solve it.  First we'll multiply both sides by five, making the first term a perfect square:

25x^2 - 10x - 10 = 0\\

Now we'll add 11 to both sides:

25x^2 - 10x + 1 = 11\\

Which makes the left side a perfect square:

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(5x - 1)^2 = 11\\\\5x - 1 =  \sqrt{11} \\\\5x = 1 + \sqrt{11}\\\\x = \frac{1 + \sqrt{11}}{5}

Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.

That gives us two answers:

x = \frac{1 + \sqrt{11}}{5}\\\\x \approx \frac{1 + 3.32}5\\\\x \approx \frac{4.32}5\\\\x \approx 0.86             x = \frac{1 - \sqrt{11}}{5}\\\\x \approx \frac{1 - 3.32}5\\\\x \approx \frac{-2.32}5\\\\x \approx -0.46

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