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Olin [163]
3 years ago
12

What are the coordinates of the image of vertex R -3,4 after a reflection across the y-axis? (–4, 3) (4, –3) (–3, –4) (3, 4)

Mathematics
2 answers:
Feliz [49]3 years ago
7 0
The coordinate of the image after being reflected is R(3,4).

When dealing with reflection of a line or shape or a figure in the coordinate plane, especially if it is reflected across the y- axis, you just have to give the opposite of the given (original) x- coordinate in order to give a symmetric figure.
Yanka [14]3 years ago
7 0

A reflection on the vertical axis is given by the following transformation:

(x, y) -----------------> (-x, y) ----------------> (x ', Y')

Applying the transformation for the point (-3, 4) we have:

(-3, 4) -----------------> (- (- 3), 4) ----------------> (3, 4)

Therefore, the new ordered pair after the reflection on the vertical axis is given by:

(3, 4)

Answer:

the coordinates of the image of vertex R -3.4 after a reflection across the y-axis are:

(3, 4)

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6.\\-6(a-7)=(-6)(a)+(-6)(-7)=-6a+42\\\\distributive\ property:\ a(b\pm c)=ab\pm ac


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Answer:

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See the diagram attached below.

Let the chords be AB and AC with common point A.

AD is the diameter. Join B with D and C with D to form two triangles.

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\begin{gathered}In\ \triangle ABD\ and \triangle ACD;\\Given\ that\ \angle BAD=\angle CAD----(condition\ 1)\\since\ AD\ is\ diameter, \angle ABD=\angle ACD = 90^0\\So\ \angle ADB=\angle ADC--------(condition\ 2)\\AD=AD\ (common\ side)-----(condition\ 3)\\ \\So\ the\ triangles\ are\ congruent\ by\ ASA\ rule.\\Hence\ AB=AC.\end{gathered}

In △ABD and△ACD;

Given that ∠BAD=∠CAD−−−−(condition 1)

since AD is diameter,∠ABD=∠ACD=90

0

So ∠ADB=∠ADC−−−−−−−−(condition 2)

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So the triangles are congruent by ASA rule.

Hence AB=AC.

3 0
3 years ago
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