If i is a normal variable: then it is -30i^2 - i*j + 20j^2
If i is the constant i, then it is 20j^2 -i*j + 30
Answer:
y=-1/2x-5
Step-by-step explanation:
First we need to put (y-3)=2(x-4) in slope intercept form.
we need to do order of operations....
so we need to first do the parenthesis
x*2= 2x
2*-4= -8
y-3=2x-8
add 3 on both sides to isolate y
y= 2x-5
so now we know the y=mx+b form
this is one line...
now we need to find out what line is perpendicular.
Perpendicular lines have opposite reciprocals slopes.
y=-1/2x-5
Quadratic formula is x = -b+ or- sq rt b^2-4ac / 2a
a=2 b=5 c=-3
-5 +or- sqrt 5^2-4(2)(-3) / 2(2)
-5 +or- sqrt 49/ 4
-5 + 7 /4 = 2/4 = 1/2
-5 - 7 /4 = -12/4 = -3
Factoring a*c is 2*-3 =-6
Factors of -6 that add to 5 are 6 and -1
Split 5x into +6x-1x
2x^2+6x-1x-3 and group
2x(x+3)-1(x+3)
(x+3)(2x-1)=0
x+3=0 gives x=-3
2x-1=0 gives x=1/2
Answer:
8:24, 24: 72, 16:48
Step-by-step explanation:
There's a lot just multiply them by the same number
