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Olin [163]
3 years ago
12

What are the coordinates of the image of vertex R -3,4 after a reflection across the y-axis? (–4, 3) (4, –3) (–3, –4) (3, 4)

Mathematics
2 answers:
Feliz [49]3 years ago
7 0
The coordinate of the image after being reflected is R(3,4).

When dealing with reflection of a line or shape or a figure in the coordinate plane, especially if it is reflected across the y- axis, you just have to give the opposite of the given (original) x- coordinate in order to give a symmetric figure.
Yanka [14]3 years ago
7 0

A reflection on the vertical axis is given by the following transformation:

(x, y) -----------------> (-x, y) ----------------> (x ', Y')

Applying the transformation for the point (-3, 4) we have:

(-3, 4) -----------------> (- (- 3), 4) ----------------> (3, 4)

Therefore, the new ordered pair after the reflection on the vertical axis is given by:

(3, 4)

Answer:

the coordinates of the image of vertex R -3.4 after a reflection across the y-axis are:

(3, 4)

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Answer:

  • A) The radius is 4 m

Step-by-step explanation:

Volume of cylinder formula:

  • V = πr²h

<h3>Given</h3>

  • V = 64π,
  • h = 4 m

Find r by substituting given values:

  • 64π = πr²*4
  • 64π = 4r²π
  • 16 = r²
  • r = √16
  • r = 4 m

Correct choice is A.

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1 year ago
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Big Time Movers charges an initial fee of $24.50, plus $12.75 an hour for their moving services. On holidays, they charge 2.5 ti
stiv31 [10]
2.5(12.75x + 24.50) = 188.75
31.875x + 61.25 = 188.75
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31.875x = 127.50
x = 127.50 / 31.875
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Advocard [28]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
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The length of a rectangle is 5959 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
lorasvet [3.4K]

Length: 2w + 59

width: w

diagonal: (2w + 59) + 2  = 2w + 61

Length² + width² = diagonal²

(2w + 59)² + (w)² = (2w + 61)²

(4w² + 118w + 3481) + w²  = 4w² + 122w + 3721

5w² + 118w + 3481 = 4w² + 122w + 3721

w² + 118w + 3481 = 122w + 3721

w² - 4w + 3481 = 3721

w² - 4w - 240 = 0

a = 1, b = -4, c = -240

w = [-(b) +/- \sqrt{(b)^{2}  - 4(a)(c) }]/2(a)

 = [-(-4) +/- \sqrt{(-4)^{2}  - 4(1)(-240) }]/2(1)

   =  [4 +/- \sqrt{(16  + 960) }]/2        

  = [4 +/- \sqrt{(976) }]/2  

  = [2 +/- 4\sqrt{(61) }]/2  

  = 1 +/- 2\sqrt{(61) }

since width cannot be negative, disregard  1 - 2√61

w = 1 + 2√61  ≈ 16.62

Length: 2w + 59  =  2(1 + 2√61) + 59  = 2 + 4√61 + 59  =  61 + 4√61  ≈ 92.24

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