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Nataly_w [17]
4 years ago
13

A 0.50 kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the a

cceleration of the frog is 3.0 meters per second^2. Calculate The magnitude of the net force exerted on the frog as it leaps.
Physics
2 answers:
BaLLatris [955]4 years ago
7 0
F = ma
F = (0.5 kg)(3 m/s^2)
F = 1.5 N
Sveta_85 [38]4 years ago
4 0
F = M a

= (0.5) (3)

= 1.5 newtons
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Answer:

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Explanation:

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f=\frac{1}{T}=\frac{1}{0.2}=\boxed{5\text{ Hz}}

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Answer:

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Explanation:

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So we can write:

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W = -36.733 J is the work performed on the car (negative because its direction is opposite to the motion of the car)

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Solving for Kf,

K_f = W+K_i = -36,733+66,120=29,387 J

The kinetic energy of the car can be also written as

K_f = \frac{1}{2}mv^2

where:

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Solving, we find

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.4 m/s

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